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3 years ago

Can you help me with this?

Mathematics

1 answer:

Firdavs [7]3 years ago

3 0

I don’t know this answer but I think it’s 81

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A paraboloid container is being filled with fluid at the rate of 4.5 cubic feet per minute. At what rate is the level of fluid c

docker41 [41]

Answer:

2.62 ft./min

Step-by-step explanation:

Just took the test.

7 0

2 years ago

W <img src="https://tex.z-dn.net/?f=4%20%5Cdiv%205" id="TexFormula1" title="4 \div 5" alt="4 \div 5" align="absmiddle" class=

ELEN [110]

Answer:.8

Step-by-step explanation:

The 5 would go on the outside

and four would go on the inside. Because 5 can't go into 4 evenly, add a decimal and a 0 after the 4. now we have 40 divided by 5. the answer is 0.8

7 0

3 years ago

What is 24.21 written in expanded form?

vodomira [7]

Answer:

(2 x 10) + (4 x 1) + (2 x 0.1) + (1 x 0.01)

Step-by-step explanation:

4 0

2 years ago

I really need this answer please help

iren2701 [21]

I’m not completely sure but I think the answer is C.

5 0

2 years ago

Find the exact length of the curve. x=et+e−t, y=5−2t, 0≤t≤2 For a curve given by parametric equations x=f(t) and y=g(t), arc len

Rama09 [41]

The length of a curve C parameterized by a vector function r(t) = x(t) i + y(t) j over an interval a ≤ t ≤ b is

$\displaystyle\int_C\mathrm ds = \int_a^b \sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2} \,\mathrm dt$

In this case, we have

x(t) = exp(t ) + exp(-t ) ==> dx/dt = exp(t ) - exp(-t )

y(t) = 5 - 2t ==> dy/dt = -2

and [a, b] = [0, 2]. The length of the curve is then

$\displaystyle\int_0^2 \sqrt{\left(e^t-e^{-t}\right)^2+(-2)^2} \,\mathrm dt = \int_0^2 \sqrt{e^{2t}-2+e^{-2t}+4}\,\mathrm dt$

$=\displaystyle\int_0^2 \sqrt{e^{2t}+2+e^{-2t}} \,\mathrm dt$

$=\displaystyle\int_0^2\sqrt{\left(e^t+e^{-t}\right)^2} \,\mathrm dt$

$=\displaystyle\int_0^2\left(e^t+e^{-t}\right)\,\mathrm dt$

$=\left(e^t-e^{-t}\right)\bigg|_0^2 = \left(e^2-e^{-2}\right)-\left(e^0-e^{-0}\right) = \boxed{e^2-\frac1{e^2}}$

5 0

2 years ago