The missing piece of information in the proof is that m∠DOA and m∠BOC are vertical opposite angles.
<h3>How to find vertically opposite angles?</h3>
We want to prove that m∠BOC = 90°.
We are given that m∠AOB is a right angle triangle. Thus;
m∠BOC must also be equal to 90°
Now, since m∠BOC and m∠AOB are right angles, then it means that we must equally say that m∠DOA and m∠BOC are vertical opposite angles and they are as such equal.
Thus, the missing piece of information in the proof is that m∠DOA and m∠BOC are vertical opposite angles.
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Simply the equation by using cross-multiplication, you get 30=5q
Then you swap sides of the equation, you get 5q=30
Then you divide both sides of the equation by 5
Your answer is q=6
Answer:
x=5
Step-by-step explanation:
Step 1: Subtract 3x from both sides.
6x−3−3x=3x+12−3x
3x−3=12
Step 2: Add 3 to both sides.
3x−3+3=12+3
3x=15
Step 3: Divide both sides by 3.
3x/3=15
x=5
Answer:
try multiplying 3x7 would be 21
Step-by-step explanation:
