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Sergeu [11.5K]
3 years ago
11

Simone told you that she placed a point on the number line that had an absolute value of 15. At what two numbers could she have

graphed her point

Mathematics
1 answer:
makvit [3.9K]3 years ago
6 0
I positive 15 and negative 15, in effect the absolute value function just removed negative signs
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Sanjay and his friends are doing a physics lab on air pressure. First, they fill a balloon with air until it reaches a pressure
KatRina [158]
Answer: After 8 hours the pressure will be at -60?

Explanation: not sure how the balloon can reach -60 kilopascals but 15% of 300 is 45 and 45 x 8(hours) is 360. 300 - 360 is -60
4 0
3 years ago
Please help me with this one too
lozanna [386]

Try B that’s what i got

4 0
4 years ago
What is the greatest value 20g of flour 3 for 3.50 or 40g of flour for 2 for 9£ which is better for money
jenyasd209 [6]

Answer:

It is better to buy 20 g of flour 3 for 3.50

Step-by-step explanation:

It is given that 20g of 3 for 3.50

It means 3 packets of 20 g is 3*20 =60

So, 60g  is for 3.50

So, 1 g =\frac{3.5}{60}=0.05833 per gram.

Now, let's find unit rate for 40 g of 2 for 9.

2 packets of 40 gram = 2* 40 =80 grams

So, 80 grams costs 9

So, 1 gram =\frac{9}{80} =0.1125

So, it is better to buy 20 g of flour 3 for 3.50

4 0
3 years ago
A driver's education course compared 1,500 students who had not taken the course with 1,850 students who had. Of those students
aivan3 [116]

Answer:

P-value is less than 0.999995 .

Step-by-step explanation:

We are given that a driver's education course compared 1,500 students who had not taken the course with 1,850 students who had.

Null Hypothesis, H_0 : p_1 = p_2 {means students who took the driver's education course and those who didn't took have same chances to pass the written driver's exam the first time}

Alternate Hypothesis, H_1 : p_1 > p_2 {means students who took the driver's education course were more likely to pass the written driver's exam the first time}

The test statistics used here will be two sample Binomial statistics i.e.;

                             \frac{(\hat p_1 - \hat p_2)-(p_1 - p_2)}{\sqrt{\frac{\hat p_1(1- \hat p_1)}{n_1} + \frac{\hat p_2(1- \hat p_2)}{n_2} } } ~ N(0,1)

Here, \hat p_1 = No. of students passed the exam ÷ No.of Students that had taken the course

 \hat p_1  = \frac{1150}{1850}            Similarly,  \hat p_2 = \frac{1440}{1500}          n_1 = 1,850       n_2 = 1,500

  Test Statistics = \frac{(\frac{1150}{1850} -\frac{1440}{1500})-0}{\sqrt{\frac{\frac{1150}{1850}(1- \frac{1150}{1850})}{1850} + \frac{\frac{1440}{1500}(1- \frac{1440}{1500})}{1500} } } = -27.38

P-value is given by, P(Z > -27.38) = 1 - P(Z > 27.38)

Now, in z table the highest critical value given is 4.4172 which corresponds to the probability value of 0.0005%. Since our test statistics is way higher than this so we can only say that the p-value for an appropriate hypothesis test is less than 0.999995 .

6 0
3 years ago
5+1/√7 - √3 + 1/√7 - √3​
dimulka [17.4K]
2.291827331. That is what I got.
3 0
3 years ago
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