A team of biologists captured and tagged 65 deer in a forest. Two weeks later, the
1 answer:
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Answer:
P = (3, 3 2/7)
Step-by-step explanation:
The desired point P is the weighted average of the end point values. The weights are the numbers in the ratio of segment lengths. The smallest weight is used for the end point closest to the largest division.
P = (5N +2M)/(5+2) = (5(7, 7) +2(-7, -6))/7 = (35-14, 35-12)/7
. P = (21, 23)/7
P = (3, 3 2/7)
_____
The x-distance from M to N is 7-(-7) = 14 units. The x-distance from P to M must be 5/(5+2) = 5/7 of that, so is (5/7)14 = 10 units. So, the x-coordinate of P is ...
Mx +10 = Px
-7 +10 = 3 . . . . x-coordinate of P
The corresponding y-coordinate can be found from a graph or by a similar calculation.
My +5/7(Ny -My) = Py
Py = -6 +(5/7)(7-(-6)) = -6 +65/7 = -6 +9 2/7 = 3 2/7 . . . . y-coordinate of P
<h3><u>Question:</u></h3>
When y is 4, p is 0.5, and m is 2, x is 2. If x varies directly with the product of p and m and inversely with y, which equation models the situation?
xpmy=8
xy/pm=8
xpm/y=0.5
x/pmy=0.5
<h3><u>Answer:</u></h3>The equation models the situation is
Given that
x is 2, y is 4, p is 0.5, and m is 2
x varies directly with the product of p and m
x varies inversely with y
x varies directly with the product of p and m
---- eqn 1
As x varies inversely with y,
----- eqn 2
From (1) and 2, we can say that
where k is constant of proportionality
---- eqn 3
On substituting given values of x = 2, y = 4, p = 0.5 and m= 2 in eqn (3) we get
Hence correct option is second that is