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V125BC [204]
3 years ago
5

Please someone help I need help

Mathematics
1 answer:
azamat3 years ago
7 0

Answer:

a b d are correct

Step-by-step explanation:

see the steps in the pic

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Sedbober [7]

Answer:

the answers are:x1=-4 and x2=5

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Number 1 Only. Please help! I don’t play cards so this is hard for me
Rudiy27
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A car traveling east at 40.0 m/s passes a trooper hiding at the roadside. The driver uniformly reduces his speed to 25.0 m/s in
Anni [7]

Step-by-step explanation:

It is given that,

Initial speed of the car, u = 40 m/s

Final speed of the car, v = 25 m/s

Time taken, t = 3.5 s

(a) We need to find the magnitude and direction of the car’s acceleration as it slows down. It can be calculated using formula as :

a=\dfrac{v-u}{t}

a=\dfrac{25-40}{3.5}

a=-4.28\ m/s^2

The acceleration is in the opposite direction of motion i.e. west.

(b) Let s is the distance the car travel in the 3.5-s time period. It can be calculated using the third equation of motion as

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{25^2-40^2}{2\times (-4.28)}

s = 113.9 meters

Hence, this is the required solution.

6 0
3 years ago
The archway of the main entrance of a university is modeled by the quadratic equation
Scilla [17]

Answer:

B. (1,5) and (5.25, 3.94)

Step-by-step explanation:

The answer is where the 2 equations intersect.

We need to solve the following system of equations:

y = -x^2 + 6x

4y = 21 - x

From the second equation:

x = 21 - 4y

Plug this into the first equation:

y = -(21 - 4y)^2 + 6(21 - 4y)

y = -(441 - 168y + 16y^2)+  126 - 24y

y = -441 + 168y - 16y^2 +  126 - 24y

16y^2 + y - 168y + 24y + 441 - 126 = 0

16y^2 - 143y + 315 = 0

y = [-(-143) +/- sqrt ((-143)^2 - 4 * 16 * 315)]/ (2*16)

y = 5, 3.938

When y = 5:

x = 21 - 4(5) = 1

When y = 3.938

x = 21 - 4(3.938) = 5.25.

3 0
2 years ago
Given: mMEJ=30°,<br> mMFJ= 50°<br> Find: mKL, mMJ
makvit [3.9K]

Applying the angles of intersecting secants theorem, the measures of the arcs are:

m(KL) = 20°; m(MJ) = 80°.

<h3>What is the Angles Intersecting Secants Theorem?</h3>

When two secants intersect and form an angle outside the circle, the measure of the angle formed is half the positive difference of the measures of the intercepted arcs.

Given the following:

  • m∠MEJ = 30°
  • m∠MFJ = 50°

m∠MEJ = 1/2(MJ - KL)

30 = 1/2(MJ - KL)

60 = MJ - KL

KL = MJ - 60

m∠MFJ = 1/2(MJ + KL)

50 = 1/2(MJ + MJ - 60)

100 = 2MJ - 60

2MJ = 100 + 60

2MJ = 160

MJ = 160/2

MJ = 80°

KL = MJ - 60 = 80 - 60

KL = 20°

Thus, applying the angles of intersecting secants theorem, the measures of the arcs are:

m(KL) = 20°; m(MJ) = 80°.

Learn more about angles of intersecting secants theorem on:

brainly.com/question/1626547

4 0
1 year ago
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