Assume ladder length is 14 ft and that the top end of the ladder is 5 feet above the ground.
Find the distance the bottom of the ladder is from the base of the wall.
Picture a right triangle with hypotenuse 14 feet and that the side opposite the angle is h. Then sin theta = h / 14, or theta = arcsin 5/14. theta is
0.365 radian. Then the dist. of the bot. of the lad. from the base of the wall is
14cos theta = 14cos 0.365 rad = 13.08 feet. This does not seem reasonable; the ladder would fall if it were already that close to the ground.
Ensure that y ou have copied this problem accurately from the original.
Answer:
18/28
Step-by-step explanation:
Answer:
40 in
Step-by-step explanation:
For a width of w, the length is 3w and the area and perimeter are ...
A = LW = (3w)(w) = 3w^2
P = 2(L+W) = 2(3w +w) = 8w
We are given the area, so we can find w to be ...
75 in^2 = 3w^2
25 in^2 = w^2 . . . . . divide by 3
5 in = w . . . . . . . . . square root
Then the perimeter is ...
P = 8w = 8(5 in) = 40 in
It’s already in standard form: 93,000,000
If we would put it in scientific notation though, it would be: 9.3 x10 ^7 (to the power of 7)
Answer:
121
.
The axis of symmetry is the line x= 6
The parabola opens downwards.
The value of h when the equation is in vertex form is positive.
Step-by-step explanation:
In the pictures.
Hope it helps! :)
