Question

I need help with this math problem.

Answer 1

Answer:

The answer to your question is s = 399.5 m

Step-by-step explanation:

Formula

                   $s = \sqrt{\frac{3V}{h}}$

Data

V = 7 500 000 m³

h = 141 m

Substitution

                  $s = \sqrt{\frac{3(7500000)}{141}}$

                  $s = \sqrt{\frac{22500000}{141}}$

                 $s = \sqrt{159574.47}$

                 s = 399.46 meters ≈ 399.5 meters

Answer 2

Answer:s = 400 meters

Step-by-step explanation:

The volume V of a pyramid with a square base with side length s and height h is

V=1/3s^2h

Solved for s, this formula gives

s = √3V/h

Given that the pyramid has a volume, V of approximately 7500000 cubic meters and the height is approximately 141 meters, the length if the side of the pyramid, s would be

s = √3 × 7500000/141

s = √3 × 53191.4894

s = √159574.4682

s = 399.468

s = 400 meters approximated to the nearest meter