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const2013 [10]
3 years ago
12

If you died with braces on would they take them off?

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
6 0

Answer:

Uhm, I don't think so could you payed for braces or your insurance paid for them.

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According to the graph, what is the value of the constant in the equation below?
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According to the graph, the value of the constant in the equation below is 80 and is denoted as option D.

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This is defined as a pictorial representation of data or variables in an organized manner.

From the equation:  Height = constant/width

We can pick any point(4,20) on the graph.

20 = c/ 4

c = 20 × 4 = 80

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Which of the following expressions is equal to 1 divided by 16
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A horizontal trough is 16 m long, and its end are isosceles trapezoids with an altitude of 4 m, a lower base of 4 m, and an uppe
Ganezh [65]

Answer:

0.28cm/min

Step-by-step explanation:

Given the horizontal trough whose ends are isosceles trapezoid  

Volume of the Trough =Base Area X Height

=Area of the Trapezoid X Height of the Trough (H)

The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)

The Volume of water in the trough at any time

Volume=\frac{1}{2} (b_{1}+4+2x)h X H

Volume=\frac{1}{2} (4+4+2x)h X 16

=8h(8+2x)

V=64h+16hx

We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles

x/h=1/4

4x=h

x=h/4

Substituting x=h/4 into the Volume, V

V=64h+16h(\frac{h}{4})

V=64h+4h^2\\\frac{dV}{dt}= 64\frac{dh}{dt}+8h \frac{dh}{dt}

h=3m,

dV/dt=25cm/min=0.25 m/min

0.25= (64+8*3) \frac{dh}{dt}\\0.25=88\frac{dh}{dt}\\\frac{dh}{dt}=\frac{0.25}{88}

=0.002841m/min =0.28cm/min

The rate is the water being drawn from the trough is 0.28cm/min.

3 0
3 years ago
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