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sergeinik [125]
3 years ago
13

Tech A says that mismatched tires may cause the ABS system to register a fault code. Tech B says that a TCS may automatically ap

ply brake pressure to a wheel brake unit even if the vehicle is not being braked. Who is correct?
Mathematics
1 answer:
sleet_krkn [62]3 years ago
5 0

Answer:

Tech A is correct

Step-by-step explanation:

Mismatched tires could activate the Antilock Braking System (ABS) indicator light because their rotational wheel speed could be dissimilar due to slight variations of tire size between different manufacturers and/or tread patterns. The ABS control module does have a fault memory and the ability to store fault codes.

A wheel speed sensor is the most common failure in the ABS system. The reason your engine management and traction control light are also on is because those systems "borrow" wheel speed information from the ABS system. The reason the fail so often is because they live in a hostile environment.

Traction Control System (TCS) allows brake actuation pressure to be generated to brake a driven wheel to prevent it spinning when peak adhesion has been lost during acceleration, and thus maintain traction by transferring the drive torque to another drive wheel that does have full adhesion.

In modern vehicles, traction-control systems utilize the same wheel-speed sensors employed by the antilock braking system. Traction control does not have the ability to increase traction; it just attempts to prevent a vehicle's wheels from spinning.

On the other hand, brake-only systems do appear to improve acceleration. It's important to remember that traction control does not affect the vehicle's ability to slow or stop in the event of a loss of control and potential crash; in short, it doesn't prevent crashes.

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I need help asap !!!
k0ka [10]

Step-by-step explanation:

180-106=74

74/2=37

m<1=37°

m<2=37°

m<3=m<1=37°

m<4=m<2=37°

m<5= 106°

7 0
3 years ago
Factor completely: 2x^3+16x^2+30x
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That is the final factored form tho?
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5 0
3 years ago
What is the solution of the system of equations?
umka21 [38]

No solution of the system of equations y = -2x + 5 and -5y = 10x + 20 ⇒ 2nd answer

Step-by-step explanation:

Let us revise the types of solutions of a system of linear equations

  • One solution
  • No solution when the coefficients of x and y in the two equations are equal and the numerical terms are different
  • Infinitely many solutions when the coefficients of x , y and the numerical terms are equal in the two equations

∵ y = -2x + 5

- Add 2x to both sides

∴ 2x + y = 5 ⇒ (1)

∵ -5y = 10x + 20

- Subtract 10x from both sides

∴ -10x - 5y = 20

- Divide both sides by -5

∴ 2x + y = -4 ⇒ (2)

∵ The coefficient of x in equation (1) is 2

∵ The coefficient of x in equation (2) is 2

∴ The coefficients of x in the two equations are equal

∵ The coefficient of y in equation (1) is 1

∵ The coefficient of y in equation (2) is 1

∴ The coefficients of y in the two equations are equal

∵ The numerical term in equation (1) is 5

∵ The numerical term in equation (2) is -4

∴ The numerical terms are different

From the 2nd rule above

∴ No solution of the system of equations

No solution of the system of equations y = -2x + 5 and -5y = 10x + 20

Learn more:

You can learn more about the system of equations in brainly.com/question/6075514

#LearnwithBrainly

7 0
4 years ago
What is 4/12 in simplest form
mylen [45]
The answer is 2/6 because both of the numbers can be divided by 2. 4/2 is 2 and 12/2 is 6
4 0
3 years ago
Read 2 more answers
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ki77a [65]

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8 0
3 years ago
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