3 years ago

1225=s^2 solve for s

2 answers:

8 0

You could solve this in one of several ways.
1) you could find the square root of both sides of the given equation, being sure to write (+.-) in front of the sqrt of 1225, or
2) you could rewrite the given equation as s^2-1225=0 and factor the result
3) you could use logarithms to solve the given equation.

Naddik [55]3 years ago

6 0

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Find the TWO integers whos product is -12 and whose sum is 1<br>

ahrayia [7]

Answer:

$\rm Numbers = 4 \ and \ -3.$

Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

$\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}$