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2 years ago

HURRY I'LL PICK A BRAINLIEST PERSON!!!

2 answers:

8 0

The answer is C. a=3/2b. To solve this problem you will nee to put A on one side and B on the other. To get this simply subtract 2b from the right and 5a from the left. You should get:
2a=3b
from this point just divide by 2 and you get: a=3/2b
Hope this helps!

Furkat [3]2 years ago

7 0

7a-2b=5a+b
2a=3b
a=3/2b

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Della bought a tree seedling that was 2 1/4 feet tall. During the first year, it grew 1 1/6 Feet. After two years, it was 5 feet

Margarita [4]

Answer:

Step-by-step explanation:

Alright, lets get started.

Della bought a tree seeding that was $2\frac{1}{4}$ feet tall means $\frac{9}{4}$ feet.

First year it grew $1\frac{1}{6}$ feet means it grew $\frac{7}{6}$ feet.

It means after 1 year, the height of tree will be = $\frac{9}{4}+\frac{7}{6}=\frac{41}{12}$

After 2 years, the height of tree is = 5 feet

So, it grew in second year = $5-\frac{41}{12}$

So, it grew in second year = $\frac{60-41}{12}=\frac{19}{12}$

So, it grew in second year= $1\frac{7}{12}$ feet. : Answer

Hope it will help :)

3 0

3 years ago

Rationalize the denominator of $\frac{5}{2+\sqrt{6}}$. The answer can be written as $\frac{A\sqrt{B}+C}{D}$, where $A$, $B$, $C$

horrorfan [7]

Answer:

$A +B+C+D = 3$ is the correct answer.

Step-by-step explanation:

Given:

$\frac{5}{2+\sqrt{6}}$

To find:

$A+B+C+D = ?$ if given term is written as following:

$\frac{A\sqrt{B}+C}{D}$

<u>Solution:</u>

We can see that the resulting expression does not contain anything under $\sqrt$ (square root) so we need to rationalize the denominator to remove the square root from denominator.

The rule to rationalize is:

Any term having square root term in the denominator, multiply and divide with the expression by changing the sign of square root term of the denominator.

Applying this rule to rationalize the given expression:

$\dfrac{5}{2+\sqrt{6}} \times \dfrac{2-\sqrt6}{2-\sqrt6}\\\Rightarrow \dfrac{5 \times (2-\sqrt6)}{(2+\sqrt{6}) \times (2-\sqrt6)} \\\Rightarrow \dfrac{10-5\sqrt6}{2^2-(\sqrt6)^2}\ \ \ \ \ (\because \bold{(a+b)(a-b)=a^2-b^2})\\\Rightarrow \dfrac{10-5\sqrt6}{4-6}\\\Rightarrow \dfrac{10-5\sqrt6}{-2}\\\Rightarrow \dfrac{-5\sqrt6+10}{-2}\\\Rightarrow \dfrac{5\sqrt6-10}{2}$

Comparing the above expression with:

$\frac{A\sqrt{B}+C}{D}$

A = 5, B = 6 (Not divisible by square of any prime)

C = -10

D = 2 (positive)

GCD of A, C and D is 1.

So, $A +B+C+D = 5+6-10+2 = \bold3$

5 0

3 years ago

How can I solve this problem?

HACTEHA [7]

Answer:

25*pi or

78.5 square units.

Step-by-step explanation:

If there was no shaded area, the area of the circle would be pi * r^2

r = 10

Area = pi * 10^2

Area = 100 * pi

Since there is a shaded area, the shaded part looks to be 1/4 of the whole. There's no indication of what it actually is, but 1/4 should be close enough.

Area_shade = 1/4 (100*pi)

Area_shade = 25 * pi

That's one answer.

Another is 25 * 3.14 = 78.5 square units

7 0

2 years ago

Rewrite x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers, to determine the a and b values.

Setler79 [48]

Answer:

Therefore values of a and b are

$a=3\ and\ b = 2$