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Artyom0805 [142]
3 years ago
14

I need help with this

Mathematics
1 answer:
Jobisdone [24]3 years ago
8 0
4 units right 1 unit up
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kids surf the internet for 35-60 minutes per day, the average is 52
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a patients dose of medication increased from 100mg to 150mg. What is the percent increase in medication?
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The answer is 50% increase. Hope this helped!

Step-by-step explanation:

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How to divide 4 by 17
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Put it as a fraction 4/17
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Can someone please help me I've been stuck on this for so long​
Vilka [71]

Answer:

x = -3, y=2

Step-by-step explanation:

x+3y =3

3y -2x =12

Solve the first equation for x

x = 3-3y

Substitute this into the second equation

3y -2(3-3y) =12

Distribute

3y -6 +6y =12

Combine like terms

9y -6 =12

Add 6 to each side

9y-6+6 =12+6

9y =18

Divide each side by 9

9y/9 =18/9

y = 2

Now find x

x = 3 -3y

x = 3-3(2)

x = 3-6

x = -3

8 0
3 years ago
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An urn contains nine red and one blue balls. A second urn contains one red and five blue balls. One ball is removed from each ur
il63 [147K]

Answer:

0.362

Step-by-step explanation:

When drawing randomly from the 1st and 2nd urn, 4 case scenarios may happen:

- Red ball is drawn from the 1st urn with a probability of 9/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this case to happen is (9/10)*(1/6) = 9/60 = 3/20 or 0.15. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 5 blue)/(8 red + 1 blue + 5 blue) = 6/14 = 3/7.

- Red ball is drawn from the 1st urn with a probability of 9/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (9/10)*(5/6) = 45/60 = 3/4 or 0.75. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 4 blue)/(8 red + 1 blue + 1 red + 4 blue) = 5/14

- Blue ball is drawn from the 1st urn with a probability of 1/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (1/10)*(5/6) = 5/60 = 1/12. The probability that a ball drawn randomly from the third urn is blue given this scenario is (4 blue)/(9 red + 1 red + 4 blue) = 4/14 = 2/7

- Blue ball is drawn from the 1st urn with a probability of 1/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this event to happen is (1/10)*(1/6) = 1/60. The probability that a ball drawn randomly from the third urn is blue given this scenario is (5 blue)/(9 red + 5 blue) = 5/14.

Overall, the total probability that a ball drawn randomly from the third urn is blue is the sum of product of each scenario to happen with their respective given probability

P = 0.15(3/7) + 0.75(5/14) + (1/12)*(2/7) + (1/60)*(5/14) = 0.362

8 0
3 years ago
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