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schepotkina [342]
3 years ago
9

Help me with these two questions pls. This is the last thing I need for the end of the school year, then I'm finally done! (20 B

rainly points for answering!!)

Mathematics
1 answer:
fiasKO [112]3 years ago
7 0

Answer: the first is direct and the second is inverse.

Step-by-step explanation: There is no variation in the Y axis on the first, but there is lots of variation in the second

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Can Somebody Please Help With This?
Alexandra [31]

Answer:

  see below

Step-by-step explanation:

A multiplier on the function value moves its y-coordinate farther from the x-axis by that multiplier value. It is the stretch factor. Stretch factors less than 1 cause the graph to be compressed vertically.

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A multiplier on the independent variable means it doesn't need to be as large to give the same function value. That is, multiplication of x by a factor of k compresses the graph horizontally by that factor of k. Equivalently, it does a horizontal stretch by a factor of 1/k.

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3 years ago
Fill in the space to complete to equality:<br><br> 3v-v²=v(__)
levacccp [35]

Answer:

3v-v² = v(3-v)

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Use distributive property on the right side of the equality.

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3 years ago
What is the equation of the line that is parallel to the given line and passes through the point (−3, 2)?
enyata [817]
You forgot to include the given line.

We need the given line to find the slope. The slope of parallel lines are equal. So, the slope of the line of the equation you are looking for is the same slope of the given line.

I can explain you the procedure to help you to find the desired equation:

1) Slope

Remember that the slope-intercept equation form is y = mx + b where m is the slope and b is thye y-intercept.

If you clear y in every equation you get:

a) y = (3/4)x + 17/4 => slope = 3/4

b) y = (3/4)x + 20/4 = (3/4)x + 5 => slope = 3/4

c) y = -(4/3)x - 2/3 => slope = -4/3

d) y = (-4/3)x - 6/3 = (-4/3)x - 2 => slope = -4/3

So, you just have to compare the slope of the given line with the above slopes to see which equations are candidates.

2) Point (-3,2)

You  must verify which equations pass through the point (-3,2).

a) 3x - 4y = - 17

3(-3) - 4(2) =  -17
- 9 - 8 = - 17
- 17 = - 17 => it is candidate

b) 3x - 4y = - 20

- 17 ≠ - 20 => it is not candidate

c) 4x + 3y = - 2

4(-3) + 3(2) = - 2
-12 + 6 = - 2
-6 ≠ -2 => it is not candidate

d) 4x + 3y = - 6

   -6 = - 6 => it is candidate

3) So, the point (-3,2) permits to select two candidates

3x - 4y = - 17, and 4x + 3y = -6.

4) Yet you have to find the slope of the given equation, if it is 3/4 the solutions is the equation 3x - 4y = -17; if it is -4/3 the solution is the equation 4x + 3y = -6.
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