Lets say the angle is a and its supplementary is b:
since a+b=180 and a=19*b,
<span>a+19a=180
20a=180
a=180/20
a=9
19a=171</span>
Let L and S represent the weights of large and small boxes, respectively. The problem statement gives rise to two equations:
.. 7L +9S = 273
.. 5L +3S = 141
You can solve these equations various ways. Using "elimination", we can multiply the second equation by 3 and subtract the first equation.
.. 3(5L +3S) -(7L +9S) = 3(141) -(273)
.. 8L = 150
.. L = 150/8 = 18.75
Then we can substitute into either equation to find S. Let's use the second one.
.. 5*18.75 +3S = 141
.. S = (141 -93.75)/3 = 15.75
A large box weighs 18.75 kg; a small box weighs 15.75 kg.
Answer: i'm pretty sure the answer is 10.5
Step-by-step explanation: <em>i multiplied 5/7 by 14.7 </em>
I'm sorry if this is wrong but if it's right i need brainliest to rank up so please mark me brainliest:)
Answer:
are you trying to get the discount amount? or the discount off the $221 if so
$221 x .32 = $70.72 discount amount off the sale price $221 which would make the final price $150.28
Step-by-step explanation: