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anastassius [24]

3 years ago

6

Three numbers a, b and c form an arithmetic sequence. The numbers b, c and a form a geometric sequence. Find the three numbers g

iven that they add up to 36.

1 answer:

MAVERICK [17]3 years ago

7 0

Answer:

They are all 12 because if you add 12 3 times you get 36 hope this helped have a nice day

Step-by-step explanation:

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Sorry for all the questions but i also need these answered but i have no idea how to answer them..:)

Allisa [31]

Answer:

did you try 12÷ by the decimal form of 3/4

4 0

3 years ago

A company did a quality check on all the packs of trail mixes it manufactured. Each pack of trail mixes is targeted to weigh 9.2

saw5 [17]

If each pack of trail mixes is targeted to weigh 9.25 oz and must be within 0.23 oz of the target in order to be accepted, then rejected masses x, are those which weighs less than 9.02 oz or greater than 9.48 oz.

4 0

3 years ago

Read 2 more answers

What of the following exponential functions is represented by the data in the table?

patriot [66]

Answer:

f(x) = ( 1/3) ^ (x)

Step-by-step explanation:

The function is

f(x) = (1/3) ^ (x)

When x = 1 f(x) = 1/3

when x=2 f(x) = 1/9

When x = -1 f(x) = ( 1/3) ^ -1 = 3/1 =3

7 0

2 years ago

28521 to the nearest tenth

ICE Princess25 [194]

28520 is your answer

7 0

3 years ago

(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop

zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

$\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})$

Compute the sample sizes as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}$

$n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}$

$=\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787$

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

$\hat p_{1}=0.45\\\hat p_{2}=0.58$

Compute the sample size as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}$

$n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}$

$=\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666$

Thus, the sample sizes are 6666.

7 0

3 years ago