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PolarNik [594]
3 years ago
15

This problem involves a limit and the greatest integer function. My current guess is B. 1/3.5. I plugged 3.5 in for x. My numera

tor became 1.5, but I rounded down to 1 because it is the greatest integer function and ended up with 2/7 or 1/3.5

Mathematics
1 answer:
Drupady [299]3 years ago
7 0
Yes your<span> answer is correct. Nice job.</span>

You should get 1 in the numerator when you plug in x = 3.5 and evaluate/simplify
In the denominator is simply 3.5

So you'll have 1/3.5 = 1/(7/2) = 2/7 as the final answer
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What set of reflections would carry triangle ABC onto itslelf?
riadik2000 [5.3K]
<h3>Answer: Choice A</h3>

y axis, x axis, y axis, x axis

============================

Explanation:

Reflecting an object over the y axis twice will have it end up in its starting position. The same can be said for the x axis as well. It doesn't matter that the x axis reflections aren't grouped next to each other, nor the y. So in a sense, two x axis reflections undo each other, so do the y axis reflections, and we end up with the same image as shown in the diagram.

6 0
3 years ago
There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=
yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = \frac{12P4}{12^{4} }

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = \frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }

P(X=2) = 0.401

P(X=3) = \frac{4C3 * 12P2}{12^{4} }

P(x=3) = 0.025

P(X=4) = \frac{12}{12^{4} }

P(X=4) = 0.001

Mean, \mu = \sum xP(x)

\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879

Standard deviation, SD = \sqrt{\sum x^{2} P(x) - \mu^{2}}  \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2}  * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}

SD = 1.033

4 0
4 years ago
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Helen [10]

The answer would be All (A)Real Numbers

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(4^7/5^2)^3 plz help
diamong [38]

Answer:

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Step-by-step explanation:

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-144 is undefined I just did this like a min ago lol but hope this works out for you if so leave a like and see if you have other questions thanks for using Brainly
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3 years ago
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