Eleven times a number X, minus a second number Y
So, The algebraic equation formed with this data is;
<h3>X×11-Y</h3>
The range is {-37,-25,-13,-1}. So you need to figure out what four numbers from this list of numbers (1,2,3,4,5,6,7,8), when applied to this
function, ( f(x)=-6x+11 ), equals these numbers that are in the range {-37,-25,-13,-1}.
So you apply each of these numbers (1,2,3,4,5,6,7,8) into the function (f(x)=-6x+11)
one by one.
f(1)=-6(1)+11=5
f(2)=-6(2)+11= -1
f(3)=-6(3)+11= -7
f(4)=-6(4)+11= -13
f(5)=-6(5)+11= -19
f(6)=-6(6)+11= -25
f(7)=-6(7)+11= -31
f(8)=-6(8)+11= -37
As you can see, f(2),f(4),f(6),and f(8) equal the numbers that are in the range {-37,-25,-13,-1}.
Answer:
1.6962 = 1.70 (2 dp)
0.4247 = 0.425 to 3 dp
0.007395 = 0.007 to 3 dp
0.007395 = 0.0074 to 4 dp
32549 = 32500 to 3 significant figures
32549 = 32550 to 4 significant figures
909520 = 910000 to 3 significant figures
909520 = 909500 to 4 significant figures
Step-by-step explanation:
1.6962 = 1.70 (2 dp)
0.4247 = 0.425 to 3 dp
0.007395 = 0.007 to 3 dp
0.007395 = 0.0074 to 4 dp
32549 = 32500 to 3 significant figures
32549 = 32550 to 4 significant figures
909520 = 910000 to 3 significant figures
909520 = 909500 to 4 significant figures
the coordinates of point f is B)7,-5
Answer:
yes no
no yes
no yes
Step-by-step explanation:
