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hodyreva [135]
3 years ago
8

Based on the rule of 72 how long will it take to double your money if you earn 7.2% interest

Mathematics
2 answers:
Readme [11.4K]3 years ago
7 0

Answer:

0.8

Step-by-step explanation:

kykrilka [37]3 years ago
7 0

Answer:

a long time

Step-by-step explanation:

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A line includes the points (4,1) and (8, 2). What is its equation in slope-intercept form?
Alisiya [41]

Answer:

y = \frac{1}{4} x  

Step-by-step explanation:

1) First, find the slope of the equation. Use the slope formula m= \frac{y_2-y_1}{x_2-x_1}. Substitute the x and y values of the given points into the formula and solve:

m = \frac{(2)-(1)}{(8)-(4)} \\m = \frac{2-1}{8-4}\\m = \frac{1}{4}

Thus, the slope is \frac{1}{4}.

2) Now, use the point-slope formula y-y_1 = m (x-x_1) to write the equation in point-slope form (from there we can convert it to slope-intercept). Substitute values for m, x_1, and y_1.

Since m represents the slope, substitute \frac{1}{4} for it. Since x_1 and y_1 represent the x and y values of one point the line intersects, choose any of the given points (it doesn't matter which one, the end result will be the same) and substitute its x and y values into the formula as well. (I chose (4,1), as seen below.) Then, isolate y to put the equation in slope-intercept form and find the answer.

y-(1) = \frac{1}{4} (x-4)\\y-1 = \frac{1}{4} x-1\\y = \frac{1}{4} x+0\\y=\frac{1}{4}x

5 0
2 years ago
12. The function M(h) = 10e-0.173h can be used to find the number of milligrams M of morphine that is
vodomira [7]

Answer:

Part A; Initial dosage is 10 milligrams

Part B:

8.4113 milligrams after 1 hour

5.0057 milligrams after 4 hours.

Step-by-step explanation:

It is given M(h)= 10 e^{-0.173h}

Initial dosage is the 10 milligrams

After 1 hour, plug in h as 1

So, M(1)=10e^{-0.173*1}

Simplify the right side

M(1)=10(0.84113)

M(1)= 8.4113 milligrams.

Now, after 4 hours

M(4)=10 e^{-0.173*4}

M(4)=10(0.50057)

M(4) =5.0057 milligrams

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3 years ago
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2-7x-3x=-8x-8\\\\-7x-3x+8x=-8-2\\\\-2x=-10 \ \ /:(-2)\\\\\huge\boxed{x=5}

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