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photoshop1234 [79]
3 years ago
12

​Although the Durham ruling in 1954 allowed mental health professionals to present information about an accused person’s mental

state, it became apparent that:
A. no mental health professional wanted to participate in court proceedings
B.mental health professionals could not reliably assess whether mental illness caused criminal behavior
C. judges were reluctant to include testimony from mental health professionals in their decisions
D. juries were reluctant to consider testimony from mental health professionals
Social Studies
1 answer:
poizon [28]3 years ago
8 0

Answer:

B.mental health professionals could not reliably assess whether mental illness caused criminal behavior

Explanation:

Judge David Bazelon was who proposed to do a scientific exam about mental illness in the criminal area. In the end, his ruling established that the defendant was not responsible for his criminal act if he was suffering from being mentally unstable. However, there is no verifiable certainty that the defendant, because of his illness, committed the crimes.

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kiruha [24]

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<em>0.964 or 96.4 %</em>

Explanation:

Hemoglobin is the red component of the red blood cell, it combines with oxygen to keep the body functional. The fractional saturation of hemoglobin is usually computed graphically but the hill equation gives a more specific value.

Calculations:

The hill equation can be expressed as;

Y_{O_{2} } =\frac{(P_{O_{2} })^{h}}{(P_{_{50} })^{h}+(P_{O_{2} })^{h}}

 Where Y_{O_{2} } is the fractional saturation of oxygen =?;

            P_{O_{2} } is the partial pressure of oxygen = 72 mm Hg;

           P_{_{50} is the partial pressure of oxygen when the hemoglobin is 50%    

                 saturated  = 24 mm Hg and;

            h is the Hill coefficient = 3.

Substituting the values into the expression above we have;

Y_{O_{2} } =\frac{(72 mm Hg_{_{} })^{3}}{(24 mm Hg_{_{} })^{3}+(72 mm Hg_{_{} })^{3}}

Y_{O_{2} } = \frac{373248}{13824 + 373248}

Y_{O_{2} }  = \frac{373248}{387072}

Y_{O_{2} } = 0.964

Therefore the fractional saturation is 0.964 or 96.4 %(multiply by 100)

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