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Mekhanik [1.2K]
4 years ago
6

Find the circumference given the area = 28.3 km². Use 3.14 for π as necessary. A. 18.9 km B. 20.8 km C. 21.4 km D. 37.8 km

Mathematics
1 answer:
Arada [10]4 years ago
3 0
<h3>Answer: choice A) 18.9 km</h3>

================================================

Work Shown:

Use the given area A = 28.3 to find the radius r

A = pi*r^2

28.3 = 3.14*r^2

3.14*r^2 = 28.3

r^2 = 28.3/3.14

r^2 = 9.01273885350319 approximately

r = sqrt(9.01273885350319)

r = 3.00212239149292

---------

Which is then used to find the circumference

C = 2*pi*r

C = 2*3.14*3.00212239149292

C = 18.8533286185756

C = 18.9

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8 0
2 years ago
How many terms are in this equation <br> 8y-6y^2/7^3
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2

Step-by-step explanation:

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4 0
3 years ago
I need help with number 14
strojnjashka [21]
The ionic compound produced would be Aluminum Oxide or Al2O3.

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7 0
3 years ago
Read 2 more answers
Find the exact values of x and r
NemiM [27]

Answer:

Below

Step-by-step explanation:

You can use sine law to solve this : sina / A = sinb / B

We will first find side x

We know that since this is a special triangle that side will = 28, but we can prove this mathematically :

sin(45) / 28 = sin(45) / x

= 28 sin(45) / sin(45)

x = 28

Now to find side r just use Pythagorean theorem a^2 + b^2 = c^2 :

c^2 = 28^2 + 28^2

      = 1568

Square root this number

r = 39.597

The just round to however your teacher wants

If you didn't already know about special triangles, an isosceles right triangle like this one has a ratio which is the two legs will equal each other, while the hypotenuse is √2a . You could have also used this to solve.

Hope this helps! Best of luck.  

3 0
3 years ago
I need the answers for these pls help
DanielleElmas [232]

Answer:

1)

A. m arc QRS = 100°

B. m arc QRT = 255°

C. m arc UTS = 180°

D. m arc UTR = 205°

2)

1] The major arc CA = 255°

2] The minor arc AB = 90°

Step-by-step explanation:

In a circle:

  • The measure of an central angle is equal to the measure of its subtended arc
  • The measure of a circle is 360°
  • Any chord divides a circle into two arcs, a minor arc its measure is < 180° and a major arc its measure is > 180°, the sum of the measures of the minor and major arcs is 360°
  • If the measures of the minor and major arcs are equal, then each arc represents a semi-circle

1)

In circle O

A.

∵ m∠QOR = 75°

∵ ∠QOR subtended by arc QR

- By using the 1st note above

∴ m of arc QR = m∠QOR

∴ m of arc QR = 75°

∵ m∠ROS = 25°

∵ ∠ROS subtended by arc RS

∴ m of arc RS = m∠ROS

∴ m of arc RS = 25°

The measure of arc QRS is the sum of the measures of arcs QR and RS

∴ m arc QRS = 75° + 25° = 100°

B.

∵ m∠SOT = 155°

∵ ∠SOT subtended by arc ST

∴ m of arc ST = m∠SOT

∴ m of arc ST = 155°

The measure of arc QRT is the sum of the measures of arcs QR, RS and ST

∴ m arc QRT = 75° + 25° + 155 °= 255°

C.

∵ m∠UOT = 25°

∵ ∠UOT subtended by arc UT

∴ m of arc UT = m∠UOT

∴ m of arc RUT = 25°

The measure of arc UTS is the sum of the measures of arcs UT and TS

∴ m arc UTS = 25° + 155° = 180°

D.

The measure of arc UTR is the sum of the measures of arcs UT, TS and SR

∴ m arc UTR = 25° + 155° + 25 = 205°

2)

1]

∵ The sum of the measures of the minor and major arcs is 360°

∵ m of minor arc AC = 105°

- Subtract 105 from 360° to find the measure of the major arc CA

∴ m of major arc CA = 360° - 105°

∴ m of major arc CA = 255°

2]

∵ m of major arc AB = 270°

- Subtract 270° from 360° to find the measure of the minor arc AB

∴ m of minor arc AB = 360° - 270°

∴ m of minor arc AB = 90°

8 0
4 years ago
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