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kotykmax [81]
3 years ago
7

The purchase price of a camera is $84. The carrying case is 12% of the purchase price. Tax 6% of the subtotal. What is the total

cost for the camera and case plus tax?
Mathematics
1 answer:
ICE Princess25 [194]3 years ago
4 0
Hi there! So, we know that the price of the camera is $84, and the carrying case is 12% of that price. Let's find the cost of the case. To find the cost of the carrying case, all you have to do is multiply the price of the camera by the percentage. 84 * 12% (0.12) is 10.08. The price of the carrying case is $10.08. Let's add that price to the price of the camera. 84 + 10.08 is 94.08. $94.08 is the purchase price, but we're not done. We must add the tax in to find the total price. We can add 100% to the tax rate of 6% to get 106% Adding 100% to the amount of tax helps us get straight to the total price. Multiply that by 94.08. 94.08 * 106% (1.06) is 99.7248 or 99.72 when rounded to the nearest hundredth. There. The total price of the purchase is $99.72.
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Answer:

Question 4:  y=\displaystyle -\frac{4}{5}x

Question 5: y=-5x-3

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: y=mx+b where <em>m</em> is the slope of the line and <em>b</em> is the y-intercept (the y-coordinate of the point where the line crosses the y-axis).

<u>Question 4</u>

<u>1) Determine the slope (</u><u><em>m</em></u><u>)</u>

\displaystyle m=\frac{y_2-y_1}{x_2-x_1} where two points that pass through the line are (x_1,y_1) and (x_2,y_2)

In the graph, two easy-to-identify points on the line are (-5,4) and (5,-4). Plug these into the equation:

\displaystyle m=\frac{-4-4}{5-(-5)}\\\\\displaystyle m=\frac{-4-4}{5+5}\\\\\displaystyle m=\frac{-8}{10}\\\\\displaystyle m=-\frac{4}{5}

Therefore, the slope of the line is \displaystyle -\frac{4}{5}. Plug this into y=mx+b as the slope (<em>m</em>):

y=\displaystyle -\frac{4}{5}x+b

<u>2) Determine the y-intercept (</u><u><em>b</em></u><u>)</u>

On the graph, we can see that the line crosses the y-axis when y is 0. Therefore, the y-intercept (<em>b</em>) is 0. Plug this into y=\displaystyle -\frac{4}{5}x+b:

y=\displaystyle -\frac{4}{5}x+0\\\\y=\displaystyle -\frac{4}{5}x

<u>Question 5</u>

<u>1) Determine the slope (</u><u><em>m</em></u><u>)</u>

\displaystyle m=\frac{y_2-y_1}{x_2-x_1}

Two easy-to-identify points are (-1,2) and (0,-3). Plug these into the equation:

\displaystyle m=\frac{-3-2}{0-(-1)}\\\\\displaystyle m=\frac{-3-2}{0+1}\\\\\displaystyle m=\frac{-5}{1}\\\\m=-5

Therefore, the slope is -5. Plug this into y=mx+b:

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<u>2) Determine the y-intercept (</u><u><em>b</em></u><u>)</u>

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y=-5x+(-3)\\y=-5x-3

I hope this helps!

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Step-by-step explanation:

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