How do you solve 4y^-3-x^2y^-1?
1 answer:
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Hello!
Answer:
1.
*The answer must have A NEGATIVE SIGN ONLY!*
2.
*The answer must have A POSITIVE SIGN ONLY!*
3.
*The answer must have a NEGATIVE SIGN ONLY!*
Step-by-step explanation:
1. 9w=-54
First, you divide by 9 both sides of an equation.
9w/9=-54/9
Simplify.
-54/9=-6
<u><em>W=-6 is the final answer.</em></u>
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2. b-12=3
First you add by 12 both sides of an equation.
b-12+12=3+12
Add by the numbers from left/right.
3+12=15
<u><em>b=15 is the final answer.</em></u>
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3. n/4=-11
First you multiply by 4 both sides of an equation.
4n/4=4(-11)
Multiply by the numbers from left/right.
4*-11=-44
<u><em>n=-44 is the final answer.</em></u>
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Hope this helps you!
Have a great day! :)
:D
-Charlie
Thanks!