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natta225 [31]
3 years ago
7

A rowing team rowed 90 miles while going with the current in the same amount of time as it took to row 10 miles going against th

e current. The rate of the
current was 4 miles per hour. Find the rate of the rowing team in still water.
Rate of the team in still water:
​
Mathematics
1 answer:
pishuonlain [190]3 years ago
8 0

Answer:

The speed in still water is 5 miles per hour.

Step-by-step explanation:

distance with current = 90 miles

distance against current = 10 miles

speed in still water = s

speed of current = 4 mph

speed with current = s + 4

speed against current = s - 4

time = t

speed = distance/time

distance = speed * time

With current:

90 = (s + 4) * t

Against the current:

10 = (s - 4) * t

We have a system of equations:

90 = (s + 4) * t

10 = (s - 4) * t

90 = ts + 4t

10 = ts - 4t

Subtract the second equation from the first equation.

80 = 8t

10 = t

t = 10

10 = t(s - 4)

10 = 10(s - 4)

1 = s - 4

s = 5

Answer: The speed in still water is 5 miles per hour.

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