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Katen [24]
3 years ago
8

(-x-¹y)°

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
3 0

a^0=1\ \text{for any real number except 0}.\\\\\text{Therefore}\ (-x^{-1}y)^0=1\ \text{for}\ x\neq0\ \text{and}\ y\neq0.\\\\a^{-1}=\dfrac{1}{a^1}\ \text{for any real number except 0}.\\\\\text{Therefore}\ w^{-1}=\dfrac{1}{w}.\\\\\dfrac{(-x^{-1}y)^0}{4w^{-1}y^2}=\dfrac{1}{4y^2\cdot\frac{1}{w}}=\dfrac{1}{4y^2}\cdot\dfrac{w}{1}=\boxed{\dfrac{w}{4y^2}}

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Explanation:

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=> A [4^2] = - C

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if A = 1/4

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That leads you to the function f(x) = [1/4] 4 ^( x - 1) - 4

2) Now you verify the images for that function for all the x-values of the table:

x = 2 => f(2) + [1/4] 4 ^ (2 - 1) - 4 = [1/4] 4 - 4 = 4 / 4 - 4 = 1 - 4 = - 3 => check

x = 3 => f(3) = [1/4] 4^ (3 - 1) - 4 = [1/4] 4^2 - 4 = 16 / 4 - 4 = 4 - 4 = 0 => check

x = 4 -> f(4) = [1/4] 4^ (4-1) - 4 = [1/4] 4^(3) - 4 = (4^3) / 4 - 4 = 4^2 - 4 = 16 - 4 = 12 => check.

Therefore, you have proved that the answer is the fourth option.
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