Answer:
300 litres.
Step-by-step explanation:
The required litres of diesel can be determined as follows:
For a distance of 594 km, 108 litres of diesel was used.
Let the number of required litres of diesel be represented by x, so that:
x = x 108
= 2.77777778 x 108
= 300
x = 300 litres
Therefore, to cover a distance of 1650 km, the required number of litres is 300.
Answer:
-3
Step-by-step explanation:
5(y+2/5)=-13
5(y+0.4)
5y + 2 =-13
5y=-13+2
5y=-15
y=-15/5
y=-3
5(-3+2/5)=-13
Answer:
In order from least to greatest: 0.25, 3 ⅜, 3 <span>⅖</span>;
Or, write as: 0.25 < 3 ⅜ < 3 ⅖ .
___________________________________
Explanation:
0.25 = ¼ l (less than "1"); the lowest of the three given values.
The remaining two values have the same whole number of 3, and a fraction:
3 <span>⅖ ;</span> and 3 ⅜.
The least common multiples among the denominators of the fraction values is 40. ⅖ = ?/40 ; 5*? =40? 5* 8 = 40, so 2*8 = 16;
Thus, ⅖ = 16/40, and 3 ⅖ = 3 16/40. 3/8 = ?/40? 8*5 =40; so 3*5 = 15 ; thus ⅜ = 15/40; and
and 3 ⅜ = 3 15/40.
3 15/40 is less than than 3 16/40;
as such; 3 ⅜ is less than 3 ⅖.
So, in order from least to greatest: 0.25, 3 ⅜, 3 ⅖;
Or, write as: 0.25 < 3 ⅜ < 3 ⅖ .
The cost of the utility pole is $707. 32
<h3>
How to determine the volume</h3>
From the information given, we have the following deductions:
- Density = 7.6 g/cm³
- Mass = Ikg = 1000g
- Cost per mass = $0. 51
Let's determine the volume of this cylinder:
Volume = mass / density
Substitute the values
Volume =
Volume = 131. 58 cm³
Thus, 131. 58 cm³ costs $0. 51
For the utility pole;
Volume = 2 πr²h
Where:
- r is 8. 8cm
- height is 750cm
Volume = 3. 142 × 8. 8 × 8. 8 × 750
Volume = 182, 487. 36 cm³
If 131. 58 cm³ costs $0. 51
Then 182, 487. 36 cm³ will cost:
= 182, 487. 36 × 0. 51/ 131. 58
= 93068. 55/ 131. 58
= $707. 32
Thus, the cost of a utility pole is $707. 32
Learn more about volume here:
brainly.com/question/10373132
#SPJ1