what?theres no picture. what does this mean?
Answer:
time tt = 40.76 s
Explanation:
In this exercise we can find the acceleration time, the speed with which the acceleration ends and the rise and flight time
For all these calculations we can use vertical launch kinematics
The speed for maximum height is zero
v² = v₀² - 2 g y
v₀ = √ 2gy
v₀ = √ (2 9.8 980)
v₀ = 138.59 m / s
The time it takes to climb after finishing the acceleration is
v = v₀ - gt
t₁ = v₀ / g
t₁ = 138.59 / 9.8
t₁ = 14.14 s
The acceleration time is
v = v₀ + a t₂
As part of the rest the initial speed is zero
t₂ = v / a
t₂ = 138.59 / 16
t₂ = 8.66 s
The height raised at this time is
y₂ = v₀ t + ½ a t²
y₂ = 0 + ½ 16 8.66²
y₂ = 600 m
Let's look for the descent time, the height of the rocket is
y = y₂ + y₁
y = 600 + 980
y = 1580 m
y = v₀t + ½ g t²
v₀ = 0
t₃ = √ 2y / g
t₃ = √ (2 1580 / 9.8)
t₃ = 17.96 s
Total flight time is
tt = t₁ + t₂ + t₃
tt = 14.14 + 8.66 + 17.96
tt = 40.76 s
1) The minute travels the circumference of a 4 inches circle is 60 minutes:
Circumference = 2πr = 2π(2in) = 4π in
Time = 60 minutes
2) Constant angular velocity => (4π / 60) = (x / 20) => x = 4π / 3 inches
x = 4.19 inches
Answer: 4.19 inches
A because the dot nearst to a
Answer:
D. drops to one quarter its original value
Explanation: