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11Alexandr11 [23.1K]
4 years ago
8

Can someone help me with 6 and 7

Physics
2 answers:
natulia [17]4 years ago
5 0
A because the dot nearst to a
nignag [31]4 years ago
3 0
A for both of the questions
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What is responsible for moving weather across the U.S.?
olga2289 [7]
Weather gets pushed around by winds created by low and high air pressure.
4 0
3 years ago
Read 2 more answers
How can you tell if something has a lot of kinetic energy? How can you tell if something only has a little bit of kinetic energy
dezoksy [38]

Based on the equation KE = 1/2(m)(v^2), Kinetic Energy can be measured based on velocity. If an object has a large velocity, it have a larger kinetic energy than if the velocity is small.

Hope this helps.

If this helped you, please vote me as brainliest!

3 0
4 years ago
Compared to the cells in a healthy body, Elisa’s cells are getting far fewer ____________________ molecules.
Elenna [48]

Answer:

glucose

Explanation:

7 0
3 years ago
You are loading a refrigerator weighing 2267 N onto a truck, using a wheeled cart. The refrigerator is raised 1.09 m to the truc
meriva

Answer:

a).

Wmin= 2471.03 J

W=1603.01 J

Explanation:

Weight, w= 2267 N

w= m*g\\W=m*g*h \\W=w*h

Minimum work 'h' is the distance the refrigerator is raised h=1.09m

W_{min}=2267 N* 1.09m\\W_{min}=2471.03 J

The motion is no frictional force so, the magnitude of the force with a angle of 45.0° is find using:

W=m*g*h'\\h'= sin(45)\\W=2267N*sin(45)\\W=1603.01 J

6 0
3 years ago
An astronomer observes electromagnetic waves emitted by oxygen atoms in a distant galaxy that have a frequency of 5.710 × 10^14
Dmitry_Shevchenko [17]

Answer:

v = 6.72 \times 10^6 m/s

Explanation:

As we know by the doppler's effect of light that when source moves with respect to stationary observer then the frequency of light received is different from its actual frequency

the relative change in the frequency of light is given by the formula

\frac{\Delta \nu}{\nu} = \frac{v}{c}

here we know that

\Delta \nu = 5.841 \times 10^{14} - 5.710\times 10^14

\Delta \nu = 1.31 \times 10^{13} Hz

now we have

\frac{1.31 \times 10^{13}}{5.841 \times 10^{14}} = \frac{v}{2.9979 \times 10^8}

v = 6.72 \times 10^6 m/s

5 0
3 years ago
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