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Sophie [7]
3 years ago
7

Need the help asp!!!

Mathematics
2 answers:
Bond [772]3 years ago
5 0

Answer:

It would be 8

Step-by-step explanation:

Katarina [22]3 years ago
5 0

Answer:

none

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=8%20%5Csqrt%7B72%7D%20" id="TexFormula1" title="8 \sqrt{72} " alt="8 \sqrt{72} " align="absmid
Ghella [55]

Answer:

8 \sqrt{72}  = 8 \sqrt{3 \times 3 \times 2 \times 2 \times 2}  \\  = 8 \times 3 \times 2  \times \sqrt{2}  = 48 \sqrt{2}

<h2><u>48√2</u> is the right answer.</h2>
7 0
3 years ago
I need help with this I need this done tomorrow please answer need help heart attack
Nataliya [291]

Basically what you have to do is multiply the two numbers that are mentioned and that will be your answer.

This is because the item will have the same amount or length and you just need to find what it will be with multiple ones.

Next time you could highlight keywords that help you understand if you are supposed to multiply, divide, subtract, or add.

3 0
3 years ago
Which is the simplified form of r^-7 + s^-12
makkiz [27]

Answer:

The simplified form of r^-7 + s^-12 is ----> 1/r^7 + 1/s^12

Step-by-step explanation:

3 0
3 years ago
Expand the following question 3t(4t-1)
Alex
You would need to distribute the 3t to the value in the parentheses to make the expression, aka answer, 12t^2-3t
7 0
4 years ago
Find the dimensions of the rectangle of largest area that has its base on the x-axis and its other two vertices above the x-axis
USPshnik [31]

If one of the vertices on the <em>x</em>-axis is (<em>x</em>, 0), then the other vertex on the same axis is (-<em>x</em>, 0), so that the rectangle has base 2<em>x</em>. The other two vertices on the parabola are the points (<em>x</em>, 6 - <em>x</em>²) and (-<em>x</em>, 6 - <em>x</em>²), so the height of the rectangle is 6 - <em>x</em>².

Then the area of the rectangle is given by the function

A(x)=2x(6-x^2)=12x-2x^3

Compute the critical points of <em>A</em>:

A'(x)=12-6x^2=0\implies x=\pm\sqrt2

So the maximum area is obtained when the vertices are the points (-√2, 0), (√2, 0), (√2, 4), and (-√2, 4). This rectangle has base 2√2 and height 4, giving a maximum area of 8√2.

6 0
4 years ago
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