All categories

3 years ago

Factor the expression 20k+50 explain every step you did

1 answer:

4 0

So, to factorise something you are taking out the highest common factor.Here, 10 is an example of the highest common factor (I’ll refer to this as HCF)

10(2k+5)

Everything inside the brakets is multiplied by what’s directly next to it (if there is a negative sign, then that is included). So, 10 x 2k = 20k and 10 x 5 = 50

10(2k + 5) is the factorised version of 20k + 50

You might be interested in

Write an expression for the lengths of the rectangle in terms

Snowcat [4.5K]

Answer:

l = A/w

Step-by-step explanation:

Let 'A' equal area. If the formula for the area of a rectangle is A = lw, you need to get 'h' alone. Divide 'h' by 'l' and by V to get the answer, l = A/w.

6 0

3 years ago

Which of the following sets are subspaces of R3 ?

Ratling [72]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

for point A:

$\to A={(x,y,z)|3x+8y-5z=2} \\\\\to for(x_1, y_1, z_1),(x_2, y_2, z_2) \varepsilon A\\\\ a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)$

$=3(aX_l +bX_2) + 8(ay_1 + by_2) — 5(az_1+bz_2)\\\\=a(3X_l+8y_1- 5z_1)+b (3X_2+8y_2—5z_2)\\\\=2(a+b)$

The set A is not part of the subspace $R^3$

for point B:

$\to B={(x,y,z)|-4x-9y+7z=0}\\\\\to for(x_1,y_1,z_1),(x_2, y_2, z_2) \varepsilon B \\\\\to a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)$

$=-4(aX_l +bX_2) -9(ay_1 + by_2) +7(az_1+bz_2)\\\\=a(-4X_l-9y_1+7z_1)+b (-4X_2-9y_2+7z_2)\\\\=0$

$\to a(x_1,y_1,z_1)+b(x_2, y_2, z_2) \varepsilon B$

The set B is part of the subspace $R^3$

for point C: $\to C={(x,y,z)|x$

In this, the scalar multiplication can't behold

$\to for (-2,-1,2) \varepsilon C$

$\to -1(-2,-1,2)= (2,1,-1)$ ∉ C

this inequality is not hold

The set C is not a part of the subspace $R^3$

for point D:

$\to D={(-4,y,z)|\ y,\ z \ arbitrary \ numbers)$

The scalar multiplication s is not to hold

$\to for (-4, 1,2)\varepsilon D\\\\\to -1(-4,1,2) = (4,-1,-2)$ ∉ D

this is an inequality, which is not hold

The set D is not part of the subspace $R^3$

For point E:

$\to E= {(x,0,0)}|x \ is \ arbitrary) \\\\\to for (x_1,0 ,0) ,(x_{2},0 ,0) \varepsilon E \\\\\to a(x_1,0,0) +b(x_{2},0,0)= (ax_1+bx_2,0,0)\\$

The $x_1, x_2$ is the arbitrary, in which $ax_1+bx_2$ is arbitrary

$\to a(x_1,0,0)+b(x_2,0,0) \varepsilon E$

The set E is the part of the subspace $R^3$

For point F:

$\to F= {(-2x,-3x,-8x)}|x \ is \ arbitrary) \\\\\to for (-2x_1,-3x_1,-8x_1),(-2x_2,-3x_2,-8x_2)\varepsilon F \\\\\to a(-2x_1,-3x_1,-8x_1) +b(-2x_1,-3x_1,-8x_1)= (-2(ax_1+bx_2),-3(ax_1+bx_2),-8(ax_1+bx_2))$

The $x_1, x_2$ arbitrary so, they have $ax_1+bx_2$ as the arbitrary $\to a(-2x_1,-3x_1,-8x_1)+b(-2x_2,-3x_2,-8x_2) \varepsilon F$

The set F is the subspace of $R^3$

5 0

3 years ago

Rewrite the equation in slope intercept form:<br> X/3+y/5=1

svet-max [94.6K]

Answer:

y=-3/5x+5

hope this helps

7 0

3 years ago

Find the difference using fraction bars or a paper and pencil. Write your answer in simplest form.

nasty-shy [4]

First, find the lowest common denominator. That is 12. You only have to change 3/4 into 12ths.

3/4 = 9/12

11/12 – 9/12 = 2/12 = 1/6

5 0

2 years ago

Read 2 more answers

If Y varies directly as X and Y= 79 when X= 49, Find Y if X = 9

ryzh [129]

Answer:

y = 14.5

Step-by-step explanation:

given that y varies directly as x

mathematically,

y ∝ x

y = kx .............................................. where k is the constant of proportionality.

k = y /x

given that

y = 79

x = 49

k = 79/49

k = 1.61

to find y when x = 9

from

y = kx

y = 1.61 × 9

y = 14.5

therefore the value of y when x = 9 in ths variation is evaluated to be equals to 14.5

7 0

3 years ago