Answer:
hey i dont really know, but look up calculator soup, it has a ton of different calculators and may be able to help u
Step-by-step explanation:
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Answer:
Columns without leading 1's in a reduced row-echelon form of the augmented matrix are called free variables. So, yes it will have 2 free variables corresponding to the two columns without leading 1. In homogeneous system it remains true.
The absolute value is very simple, since:
- The absolute value of a positive number is the number itself
- The absolute value of a negative number is that same number, without the minus sign.
So, the absolute value of -2/3 is simply 2/3:
![\left| -\dfrac{2}{3} \right| = \dfrac{2}{3}](https://tex.z-dn.net/?f=%20%5Cleft%7C%20-%5Cdfrac%7B2%7D%7B3%7D%20%5Cright%7C%20%3D%20%5Cdfrac%7B2%7D%7B3%7D%20)
Well she has already read up to page 782, so the remaining pages are C.
Lets convert all of them to decimals first to make it a little easier.
-
= -0.75
0.5
= 0.67
-
= -2.33
1.2
So in order from Least to Greatest:
{(-2.33), (-0.75), 0.5, 0.67, 1.2} OR IN ORIGINAL FORM {-
, -
, 0.5,
, 1.2}
In order from Greatest to Least:
{1.2, 0.67, 0.5, (-0.75), (-2.33)} OR IN ORIGINAL FORM {1.2,
, 0.5, -
, {-![\frac{7}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B3%7D)
Hope that helps!