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ladessa [460]
4 years ago
8

A ball is dropped from a height of 100 meters. How long will it take to hit the ground? Show work

Physics
1 answer:
SCORPION-xisa [38]4 years ago
5 0

20.4081/s^2

Explanation:

ignoring air resistance and with the knowledge that the acceleration of gravity is 9.8 we can use that to find the answer.

The formula is (hX2)/(9.8m/s^2)

so

100mX2 = 200m

200m/9.8m/s^2 = 20.4081/s^2

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An airplane flies horizontally at constant speed in a straight­line direction. Its state of motion is unchanging. In other words
Alex_Xolod [135]

Answer:

sum of all forces on the air plane must be ZERO

So both forces must be of same magnitude

Explanation:

As we know that airplane is moving with uniform speed is horizontal plane is a straight line

so the motion of the air plane is uniform without any acceleration

So we will have

a = 0

acceleration must be zero

now by Newton's law

F_{net} = 0

F_1 + F_2 = 0

so sum of all forces on the air plane must be ZERO

7 0
3 years ago
30 PTS
tigry1 [53]
Spreads out in the medium, first choice
7 0
3 years ago
Which of the following is NOT a true statement about error in hypothesis​ testing?Choose the correct answer below.A.The symbol a
Marizza181 [45]

Answer:

Option D

A type I error is making the mistake of rejecting the null hypothesis when it is actually false.

Explanation:

Error type I is usually represented by alpha symbol and type I error entail making a mistake of rejecting the  null hypothesis when it's actually true. Type II error on the other side involves making a mistake of failing to reject null hypothesis when it is actually false. The statement in option D is false because it contradicts the definition of type I error above hence the only false statement in relation to hypothesis testing is option D, A type I error is making the mistake of rejecting the null hypothesis when it is actually false.

8 0
4 years ago
The cross sectional area of an optical fibre is 6.3 x 10^-6 m^2 The intensity of the light entering the optical fibre is 3.2 x 1
gogolik [260]

the answer is 0.0. also known as a emoji face!

7 0
3 years ago
Situation: two electrons, each with mass m and charge q, are released from positions very far from each other. With respect to a
Ahat [919]

Answer:

r_{min}=\frac{kq^2}{5m_ev^2}

Explanation:

The total kinetic energy of both electrons will be electrostatic potential energy, when the electrons reach the minima distance due to electrostatic repulsion. Then, you have:

E_{k}=U_E\\\\\frac{1}{2}m_ev_1^2+\frac{1}{2}m_ev_2^2=k\frac{q^2}{r_{min}}

me: mass of the electron

q: charge of the electron

k: Coulomb's constant

you take into account that v2=3v1=3v and do rmin the subject of the formula:

\frac{1}{2}m_e[v^2+9v^2]=5m_ev^2=k\frac{q^2}{r_{min}}\\\\r_{min}=\frac{kq^2}{5m_ev^2}

4 0
4 years ago
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