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Elden [556K]
3 years ago
5

What makes a good scientific question? (1 point)

Physics
1 answer:
liraira [26]3 years ago
7 0

C. It is answered by observation and evidence.

Good scientific explanations are defined, measurable and controllable. They can be answered by an experiment.

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a soccer player is running at 6m/s. he then stumbles over an opponents foot falling, and rolling to a stop. this took 4 seconds.
Natali [406]

a =  \frac{(vf - vi)}{t}  \\ a =  \frac{0 - 6}{4} \\ a =  - 1.5 \frac{m}{ {s}^{2} }
top one is the formula
mid- i plug in the numbers
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8 0
3 years ago
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If only a green light shown on a bunny that has black and white fur, what would the bunny look like?
nataly862011 [7]
The white fur reflects all colors, so would appear green.
The black fur reflects no colors, so would still appear black.
3 0
3 years ago
Determine the work done by the constant force. The locomotive of a freight train pulls its cars with a constant force of 15 tons
Digiron [165]

Answer:

5.92×10⁷ J

Explanation:

We'll begin by converting 15 tons to Newton. This can be obtained as follow:

1 ton = 9806.65 N

Therefore,

15 ton = 15 ton × 9806.65 N / 1 ton

15 ton = 147099.75 N

Next, we shall convert one-quarter (¼) or 0.25 mile to metre. This can be obtained as follow:

100 mi = 160934 m

0.25 mi = 0.25 mi × 160934 / 100 mi

0.25 mi = 402.335 m

Finally, we shall determine the Workdone. This can be obtained as follow:

Force (F) = 147099.75 N

Distance (d) = 402.335 m

Workdone (Wd) =?

Wd = F × d

Wd = 147099.75 × 402.335

Wd = 5.92×10⁷ J

Thus, the Workdone is 5.92×10⁷ J

5 0
2 years ago
Is the the last half of the month waxing or waning( talking about moon phases
rewona [7]
Its not really definable. Say, you can have a full moon on the last day of November, and have the waning phases throughout the first half. Or you can have a new moon on the last day of December, and have the waxing phases during the first half of the month.
\
5 0
3 years ago
With what tension must a rope with length 2.20 m and mass 0.150 kg be stretched for transverse waves of frequency 43.0 hz to hav
Blababa [14]

Solution:

v=sqrt(\frac{t}{u})\\v=40\times0.80=32m/s\\\frac{t}{u}=900\\t=900\times\frac{0.150}{2.20}\\=61.36N


5 0
3 years ago
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