The leaf fell at the crooked path instead of straight down because air currents and gravity applied changing and unbalanced forces to the leaf.
<h3>What is an air current?</h3>
An air current is defined as the changes in atmospheric pressure that causes the movement of air from one area to another.
When a leaf is detached naturally from the tree, it won't fall straight down to the floor but will fall a distance away from the tree due to the action of air current and some unbalanced forces.
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The potential difference between the two ends of the circuit is the electric potential difference. The electric potential difference and the work will be 10V and 1.6 x 10^-18 J respectively.
<h3>What is an electric field?</h3>
An electric field is an electric property that is connected with any location in space where a charge exists in any form. The electric force per unit charge is another term for an electric field.
The given data in the problem is given by;
E is the electric field = (200 N/C)
d is the distance = 5.0 cm.=0.05 m
Q is the charge of electrons= 1.602 x 10^-19 C
The formula for electric potential is given by;


The work is defined as the product of the potential difference and charge of an electron.

Hence the electric potential difference and the work will be 10V and 1.6 x 10^-18 J respectively.
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B is the correct answer.
A is incorrect because energy is neither created nor destroyed.
C is incorrect because kinetic energy would keep the ball rolling, so that would not make sense.
Answer:
Weight of an object = 225 newtons
Explanation:
Given:
Mass = 60 kilograms
Acceleration due to gravity = 3.75 m/s²
Find:
Weight of an object
Computation:
Weight of an object = Mass x Acceleration due to gravity
Weight of an object = 60 x 3.75
Weight of an object = 225 newtons
Answer:
1/4 λ film
Explanation:
Let L = total path length then L = 2 t where t is film thickness
There will be a 180 deg phase change at the air-film interface but no
phase change at the film-air interface
L = n * wavelength / 2 where n = 1, 3, 5, 7 etc
(the total path L must be an odd number of 1/2 wavelengths)
Or t = n * wavelength / 4 (the film must be an odd number
of 1/4 wavelengths thick)
1/4 λ film satisfies this condition
Note: Find the missing diagram in the attachment section.