Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
Answer:
Option: c is correct.
Step-by-step explanation:
We are given that paco needs at least 3/8 yard of twine to build a model ship.
that is we require twine of amount greater than 3/8 yards.
<em>now we need to check among the given options which quantity is greater than 3/8 yards.</em>
a)
3/10 yard.
As we know that for two rational numbers with the same numerator but with different denominator the number whose denominator is smaller is a greater quantity.
Hence 3/10 < 3/8
Hence option a is incorrect.
b)
1/4 yard
As to compare to rational numbers we have to either make the numerator equal or their denominator equal. Hence here we multiply and divide 1/4 by 2 to get 8 in the denominator.

as 2/8 < 3/8
since the denominator is same and the number with the same denominator but with different numerator are compared as whose numerator is greater is a greater quantity.
Hence option b is incorrect.
c)
3/4 yard
Clearly both the numbers have the same numerator but different denominator and we know that for two rational numbers with the same numerator but with different denominator the number whose denominator is smaller is a greater quantity.
Hence 3/8 < 3/4
Hence, option c is correct.
d)
1/8 yard
clearly both the numbers have the same denominator and we know that for two rational numbers withe same denominator but with different numerator the number whose numerator is smaller is a smaller quantity.
Hence, 1/8 < 3/8
Hence, option d is incorrect.
Answer:
P(A)=0.55
P(A and B)=P(A∩B)=0.1265
P(A or B)=P(A∪B)=0.7635
P(A|B)=0.3721
Step-by-step explanation:
P(A')=0.45
P(A)=1-0.45=0.55
P(B∩A)=?
P(B|A)=0.23
P(B|A)=(P(A∩B))/P(A)
0.23=(P(A∩B))/0.55
P(A∩B)=0.23×0.55=0.1265
P(A∪B)=P(A)+P(B)-P(A∩B)
=0.55+0.34-0.1265
=0.7635
P(A|B)=[P(A∩B)]/P(B)=0.1265/0.34 ≈0.3721
Answer:
The 95% confidence interval is ( 27.126 , 34.674)
Step-by-step explanation:
Given
The t critical value at 0.05 level = 2.023 for the df = 39
Confidence interval = 95%
Mean

Substituting the given values we get -

Hence, the 95% confidence interval is
( 27.126 , 34.674)
C = kmt
k = C/mt
Units of k are Calories per pound - minute.