a ladybug crawls vertically on a leaf. its motion is shown on the following graph of vertical position y vs time t what is the a
verage speed of the ladybug between the times t=4s and t=7s
2 answers:
Explanation:
The attached figure shows the position-time graph of a ladybug. We need to find the average speed of the ladybug between t = 4 s to t = 7 s.
We know that, the slope of a position-time graph gives velocity of an object. It can be given by :
In this case, the position of a ladybug at t = 4 s and at t = 7 s is the same i.e. 2 m.
It means its velocity is equal to at this time or we can say that ladybug is at rest.
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Answer:
The asteroid requires 5.14 years to make one revolution around the Sun.
Explanation:
Kepler's third law establishes that the square of the period of a planet will be proportional to the cube of the semi-major axis of its orbit:
(1)
Where T is the period of revolution and a is the semi-major axis.
In the other hand, the distance between the Earth and the Sun has a value of . That value can be known as well as an astronomical unit (1AU).
But 1 year is equivalent to 1 AU according with Kepler's third law, since 1 year is the orbital period of the Earth.
For the special case of the asteroid the distance will be:
That distance will be expressed in terms of astronomical units:
⇒
Finally, from equation 1 the period T can be isolated:
Then, the period can be expressed in years:
Hence, the asteroid requires 5.14 years to make one revolution around the Sun.