a ladybug crawls vertically on a leaf. its motion is shown on the following graph of vertical position y vs time t what is the a
verage speed of the ladybug between the times t=4s and t=7s
2 answers:
Explanation:
The attached figure shows the position-time graph of a ladybug. We need to find the average speed of the ladybug between t = 4 s to t = 7 s.
We know that, the slope of a position-time graph gives velocity of an object. It can be given by :
In this case, the position of a ladybug at t = 4 s and at t = 7 s is the same i.e. 2 m.
It means its velocity is equal to at this time or we can say that ladybug is at rest.
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The velocity of the car was 4.93m/s and the direction was northeast.
<h3>Calculation</h3>It is given,
time of the trip = t = 3 minutes = 180 seconds
1st distance A = 1500ft = 457.2m east
2nd distance B = 2500ft = 762m north
We are asked to find the average velocity.
First, we get the resultant distance magnitude by applying Pythagoras theorem to find the hypotenuse.
Then we have
Velocity = Distance/time
Velocity = 888.63/180
Velocity = 4.93 m/s
Then the direction is northeast.
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