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Serjik [45]
3 years ago
10

Images formed by a convex mirror are always ​

Physics
1 answer:
gladu [14]3 years ago
4 0

Answer:

Images formed by a convex mirror are always ​virtual

Explanation:

A virtual image is always created by a convex mirror, and it is always situated behind the mirror. The picture is vertical and situated at the focus point when the item is far away from the mirror. As the thing approaches the mirror, the image follows suit and increases until it reaches the same height as the object.

<u>OAmalOHopeO</u>

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Two or more velocities add by ____?<br><br> Plz help
VladimirAG [237]
By vector addition.
In fact, velocity is a vector, with a magnitude intensity, a direction and a verse, so we can't simply do an algebraic sum of the two (or more velocities). 
First we need to decompose each velocity on both x- and y-axis (if we are on a 2D-plane), then we should do the algebraic sum of all the components on the x- axis and of all the components on the y-axis, to find the resultants on x- and y-axis. And finally, the magnitude of the resultant will be given by
R= \sqrt{(R_x)^2+(R_y)^2}
where Rx and Rx are the resultants on x- and y-axis. The direction of the resultant will be given by
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3 0
3 years ago
Read 2 more answers
An object with a charge of −2.1 μC and a mass of 0.0044 kg experiences an upward electric force, due to a uniform electric field
zheka24 [161]

Answer:

(1) 2.05 x 10^4 N/C

(2) Downward

(3) upward, 9.8 m/s^2

(4) upward, 9.8 m/s^2

Explanation:

q = - 2.1 micro coulomb, m = 0.0044 kg, g = 9.8 m/s^2

(1) The electric force is given by F = - q x E

The magnitude of electric force is balanced by the weight of the charged particle

q x E = m x g

E = mg / q

E = \frac{0.0044 \times 9.8}{2.1 \times 10^{-6}}

E = 2.05 x 10^4 N/C

(2) As the electric force is acting upward and the weight is downward so the elecric field is in downward direction.

(3) The charge is doubled,

then the electric field becomes half.

E = 2.05 x 10^4 / 2 = 1.025 x 10^4 N/C

The direction is same that is in downward direction.

Acceleration = Force / mass

a = mg / m = 9.8 m/s^2 upward

(4) The charge is doubled,

then the electric field becomes half.

E = 2.05 x 10^4 / 2 = 1.025 x 10^4 N/C

The direction is same that is in downward direction.

Acceleration = Force / mass

a = mg / m = 9.8 m/s^2 upward

7 0
3 years ago
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Elan Coil [88]
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5 0
3 years ago
In the qualifying round of the 50-yd freestyle in the sectional swimming championship, Dugan got an early lead by finishing the
Nata [24]

Answer:

v = 0

Explanation:

Given that,

Total distance is 50 yards

Dugan got an early lead by finishing the first 25.00 yd in 10.01 seconds

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We need to find Dugan's average velocity for the entire race. As he returns at the initial position. As a result, the net displacement is equal to 0. So,

Average velocity = net displacement/time

v = 0

Hence, his average velocity for the entire race is 0.

6 0
4 years ago
What is the force on a 1670kg elevator accelerating at 6m/s square?
marshall27 [118]

As per Newton's 2nd law

we know that

F = ma

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here we know that

m = 1670 kg

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a = 6 m/s^2

so from above equation we have

F = 1670 * 6

F = 10020 N

so the force here will be 10020 N

7 0
3 years ago
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