Vf = Final velocity.
Vi = initial velocity
a = acceleration.
t = time
Vf = Vi + at
Vf = 0 + (2 m/s^2)(3s)
Vf = 6 m/s south
To solve this problem it is necessary to apply the concepts related to the kinematic equations of movement description.
From the definition we know that the speed of a body can be described as a function of gravity and height



Then applying the kinematic equation of displacement, the height can be written as

Re-arrange to find t,



Thus the calculation of the displacement would be subject to



Therefore the required distance must be 0.547m
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