Question

You drive a car 1500 ft to the east, then 2500 ft to the north. if the trip took 3.0 minutes, what were the direction and magnitude of your average velocity?

Answer 1

The velocity of the car was 4.93m/s and the direction was northeast.

Calculation

It is given,

time of the trip = t = 3 minutes = 180 seconds

1st distance A = 1500ft = 457.2m east

2nd distance B = 2500ft = 762m north

We are asked to find the average velocity.

First, we get the resultant distance magnitude by applying Pythagoras theorem to find the hypotenuse.

$A^{2} + B^{2} =C^{2} \\C=\sqrt[]{A^{2} +B^{2} } \\C=\sqrt{457.2^{2} +762^{2} } \\C= 888.63m$

Then we have

Velocity = Distance/time

Velocity = 888.63/180

Velocity = 4.93 m/s

Then the direction is northeast.

To know more about Pythagoras theorem, visit:

brainly.com/question/343682

#SPJ4