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tino4ka555 [31]

2 years ago

6

Which type of plate boundary is most closely associated with the formation of new ocean floor?

1 answer:

Ludmilka [50]2 years ago

5 0

Answer:

C) Divergent

Explanation:

Magma which is present in the underlying mantle comes out at divergent plate boundaries. The reason of coming out magma is that heat in the mantle makes the crust less dense. After coming out, magma cools down and solidifies to form a new ocean floor. Hence, divergent plate boundary is most closely related with formation of new ocean floor.

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You can see your image in a shiny, flat surface because the light waves are bouncing off the surface back at you. This is an exa

Alexxx [7]

I think it would be Reflection because the light in the ray reflects off of any flat or shiny object.... Hope this helps ^-^....

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2 years ago

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Which resistors in the circuit must always have the same current?

kakasveta [241]

Answer:

Resistors in series in the circuit must always have the same current

Explanation:

Resistors are said to be connected in series if they are connected one after another.

The total resistance in the circuit with resistors connected in series is equal to the sum of individual resistances.

Individual resistors in series do not get the total source voltage. Total source voltage divide among them.

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The current through a 10 ohm resistor connected to a 120 volt power supply is

Leno4ka [110]

Answer:I=12 A

Explanation:

Given

Resistance $R=10 \Omega$

Voltage $V=120 V$

According to ohm's law current through a conductor is directly proportional to the voltage applied.

$V\propto I$

$V=IR$

where V=Voltage

I=Current

R=resistance

$I=\frac{V}{R}$

$I=\frac{120}{10}$

$I=12 A$

4 0

2 years ago

An electron is released from rest in a weak electric field given by E =-2.30 x 10-10 N/Cj. After the electron has traveled a ver

Goshia [24]

Explanation:

It is given that,

An electron is released from rest in a weak electric field of, $E=2.3\times 10^{-10}\ N/C$

Vertical distance covered, $s=1\ \mu m=10^{-6}\ m$

We need to find the speed of the electron. Let its speed is v. Using third equation of motion as :

$v^2-u^2=2as$

$v^2=2as$ .............(1)

Electric force is $F_e$ and force of gravity is $F_g$ . As both forces are acting in downward direction. So, total force is:

$F=mg+qE$

$F=9.1\times 10^{-31}\times 9.8+1.6\times 10^{-19}\times 2.3\times 10^{-10}$

$F=4.57\times 10^{-29}\ N$

Acceleration of the electron, $a=\dfrac{F}{m}$

$a=\dfrac{4.57\times 10^{-29}\ N}{9.1\times 10^{-31}\ kg}$

$a=50.21\ m/s^2$

Put the value of a in equation (1) as :

$v=\sqrt{2as}$

$v=\sqrt{2\times 50.21\times 10^{-6}}$

v = 0.010 m/s

So, the speed of the electron is 0.010 m/s. Hence, this is the required solution.

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3 years ago

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Tresset [83]

a minute or less than a minute

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