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3 years ago

Which type of plate boundary is most closely associated with the formation of new ocean floor?

Physics

1 answer:

Ludmilka [50]3 years ago

5 0

Answer:

C) Divergent

Explanation:

Magma which is present in the underlying mantle comes out at divergent plate boundaries. The reason of coming out magma is that heat in the mantle makes the crust less dense. After coming out, magma cools down and solidifies to form a new ocean floor. Hence, divergent plate boundary is most closely related with formation of new ocean floor.

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Which of the following stars is likely to be the coldest? Select one: a. The white-colored star b. The orange-colored star c. Th

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The White colored star is likely to be the coldest

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3 years ago

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Two water jets are emerging from a vessel at a height of 50 centimeters and 100 centimeters. If their horizontal velocities at t

givi [52]

For t1:

t1 = square root of 2h1 / g = square root of 2 * 0.5 / 9.8 = 0.319 sec

For t2:

t2 = sqaure root of 2h2 / g = square root of 2 * 1.0 / 9.8 = 0.451 sec

Wherein:
t = time(s) for the vertical movement
h= height
g = gravity (using the standard 9.8 m/sec measurement)

d1 = 1*0.319 = 0.319 m
d2 = 0.5 * 0.451 = 0.225 m

Where:

d = hor. distance

ratio = d1:d2
= 0.319 : 0.225
=3.19 : 2.25

The answer is 3.19 : 2.25

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3 years ago

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You kick a soccer ball across a field the ball travels across the field and slowly comes to a stop. Since the ball slowly comes

marysya [2.9K]

Answer:

It slowly decreases and the friction acting on it slowing it down becomes the bigger net force, if that makes sense :)

Explanation:

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3 years ago

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Answer:

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3 years ago

Please, I need help!!

Masja [62]

The box has weight 50.0 N (a downward force), from which we can determine its mass $m$ :

$-50.0\,\mathrm N=m(-g)=m\left(-9.80\,\dfrac{\mathrm m}{\mathrm s^2}\right)\implies m=5.10\,\mathrm{kg}$

The box's acceleration is taken to be uniform, which means its acceleration due to the frictional force (which acts in the leftward direction) at any time during the $\Delta t=t_2-t_1=2.25\,\mathrm s$ interval is

$\vec a=\dfrac{0-1.75\,\frac{\mathrm m}{\mathrm s}}{2.25\,\mathrm s}=-0.778\,\dfrac{\mathrm m}{\mathrm s^2}$

Then the friction force has magnitude $F$ (where the vector is acting in the leftward direction) satisfies

$\vec F=m\vec a\implies-F=(5.10\,\mathrm{kg})\left(-0.778\,\dfrac{\mathrm m}{\mathrm s^2}\right)\implies F=3.97\,\mathrm N$

and the closest answer would be A.

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3 years ago