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dusya [7]
3 years ago
7

HELP ME PLEASEEE!!!!!!!!!

Chemistry
1 answer:
igor_vitrenko [27]3 years ago
6 0
The picture is blurry on my hand
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What is the complete ionic equation for NaOHaq plus HCIaq equals H2OI plus NaCIaq?
OverLord2011 [107]

Answer:

Ionic equation:

Na⁺(aq) + OH⁻(aq) + H⁺(aq) + Cl⁻(aq)   →  H₂O(l) + Na⁺(aq) + Cl⁻ (aq)

Explanation:

Chemical equation:

NaOH(aq) + HCl(aq)   →  H₂O(l) + NaCl (aq)

Balanced chemical equation:

NaOH(aq) + HCl(aq)   →  H₂O(l) + NaCl (aq)

Ionic equation:

Na⁺(aq) + OH⁻(aq) + H⁺(aq) + Cl⁻(aq)   →  H₂O(l) + Na⁺(aq) + Cl⁻ (aq)

Net ionic equation:

OH⁻(aq) + H⁺(aq)    →  H₂O(l)

The  Cl⁻(aq)  and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

3 0
2 years ago
Which is a property of barium (Ba)?
777dan777 [17]

Answer:

i think but i am not sure but according to me it mainly reacts yo non metals and i think its very reactive if my answer is wrong then comment below this question i will see it and i will get an opportunity to learn something new

4 0
3 years ago
Transition metals when moving from left to right on the periodic table?
Ierofanga [76]

Answer:

True

Explanation:

5 0
3 years ago
What purpose does fecl3 serve in the electrophilic aromatic substitution reaction between chlorine and benzene?
maria [59]
The reason does FeCl3 serve in the electrophilic sweet-smelling substitution response amongst chlorine and benzene is that it fills in as a Lewis corrosive impetus by responding with the Cl2 and along these lines actuates it toward assault by benzene's π electrons.
6 0
3 years ago
What mass of solute should you measure out in order to make 1,000 mL of a 0.3 M solution of magnesium phosphate Mg3(PO4)2?
vivado [14]

Hey there !

Molecular Weight: 262.86 g/mol

Volume in liters : 1,000 mL => 1,000 / 1000 => 1 L

Number of moles of solution :

number of moles = volume x molarity

number of moles = 1 x 0.3  => 0.3 moles

Therefore:

1 mole Mg₃(PO₄)₂ ------------------- 262.86 g

0.3 moles ----------------------------- mass of Mg₃(PO₄)₂  ??

mass of Mg₃(PO₄)₂ = 0.3 x 262.86 / 1

mass of Mg(PO₄)₂ => 78.858 g

Hope this helps!

7 0
2 years ago
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