Answer:
See Explanation
Explanation:
Number of moles of NaOH = 0.3868 L × 1.707 M = 0.660 moles
Reaction of Al^3+ and OH^-
Al^3+(aq) + 3OH^-(aq) -----> Al(OH)3(s)
If 1 mole of Al3+ reacts with 3 moles of OH^-
x moles of Al^3+ reacts with 0.660 moles of OH^-
x = 1 × 0.660/3
x= 0.22 moles
Mass of Al^3+ = 0.22 moles × 27 g/mol = 5.94 g of Al^3+
Co^2+(aq) + 2OH^-(aq) ----> Co(OH)2(s)
1 mole of Co^+ reacts with 2 moles of OH^-
x moles of Co^2+ reacts with 0.660 moles of OH^-
x = 1 × 0.660/2 = 0.33 moles
Mass of Co^2+ = 0.33 moles × 59 g/mol = 19.47 g
Answer:
A
Explanation:
bc u have to think about it
Answer:
%age Yield = 87.16 %
Explanation:
Percentage yield is the ratio of actual yield to theoretical yield. The actual yield the amount of product obtained after the experiment and the theoretical yield is the amount of ideal product obtained on paper calculations. The actual yield is almost always less than the theoretical yield due to chemical reaction problems, or handling problems.
Given Data:
Theoretical Yield = 25.31 g
Actual Yield = 22.06 g
%age Yield = ?
Formula Used:
%age Yield = (Actual Yield ÷ Theoretical Yield) × 100
Putting Values,
%age Yield = (22.06 g ÷ 25.31 g) × 100
%age Yield = 87.16 %
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