<h3>
Answer:</h3>
C₅H₁₂O(l)+15/2O₂(g)→5CO₂(g)+6H₂O(l)
<h3>
Explanation:</h3>
The balanced chemical equation for the combustion of the hydrocarbon in question is;
C₅H₁₂O(l)+15/2O₂(g)→5CO₂(g)+6H₂O(l)
- A balanced chemical equation is one in which the number of atoms of each element is equal on both sides of the equation.
- Reactant side has; 5 carbon atoms, 12 hydrogen atoms and 16 Oxygen atoms
- Product side has; 5 carbon atoms, 12 hydrogen atoms and 16 Oxygen atoms
- An equation is balanced by putting appropriate coefficients on reactants and products involved in the reaction.
- An equation is balanced so as to obey the law of conservation of mass.
C. carbon
sodium is an
oxygen is o
cl is chlorine
They exist in the outer orbitals
Atomic weight is actually calculated by the sum of protons and neutrons of that atom. It is not equal to the number. You must add them for the result
