Answer:
Step-by-step explanation:
To inscribe a circle in a given triangle PQR means to construct a circle in the triangle PQR. The incenter of a triangle is the midpoint in the triangle, which can be located by bisecting the three angles of the triangle individually.
The construction is shown in the attachment.
<span>The vertex of the parabola is the highest or lowest point of the graph.
</span><span>y=-4x^2+8x-12 = -4 (x^2 -2x +3)
Lets work with this now: </span>x^2 -2x +3
x^2 -2x +3 -> what is the closeset perfect square?
x^2 -2x +1 = (x-1)^2
So
x^2 -2x +3 = (x-1)^2 +2
Replacing to original
y=-4x^2+8x-12 = -4 (x^2 -2x +3) = -4 ((x-1)^2 +2) = -4 (x-1)^2 - 8
The min or max point is where the squared part = 0
So when x=1 , y= -4*0-8=-8
This will be the max of the parabola as there is - for the highest factor (-4x^2)
The max: x=1, y= -8
Answer:
k = -2
Step-by-step explanation:
x -1 0 2 5
f(x) 2 0 -4 -10
ƒ(x) = kx
Substitute a pair of values for x and ƒ(x)
-10 = k×5
Divide each side by 5
k = -2
The constant of variation k = -2.
