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Ghella [55]
3 years ago
12

The function 3(2)t models the number of leaves on a plant, where t represents the number of weeks since it was planted. Which st

atement is the best interpretation of one of the values in this function? A) The number of leaves increases by 6 each week. B) The initial number of leaves on the plant was 2. C) The initial number of leaves on the plant was 3. D) The number of leaves on the plant increases by 3% each week.
Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
3 0

Answer:

C) The initial number of leaves on the plant was 3.

Step-by-step explanation:

The plant has initially 3 leaves and is multiplied by 2 every week. Therefore, the answer is C.

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Evaluate the integral. 3 2 t3i t t − 2 j t sin(πt)k dt
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∫(t = 2 to 3) t^3 dt

= (1/4)t^4 {for t = 2 to 3}

= 65/4.

----

∫(t = 2 to 3) t √(t - 2) dt

= ∫(u = 0 to 1) (u + 2) √u du, letting u = t - 2

= ∫(u = 0 to 1) (u^(3/2) + 2u^(1/2)) du

= [(2/5) u^(5/2) + (4/3) u^(3/2)] {for u = 0 to 1}

= 26/15.

----

For the k-entry, use integration by parts with

u = t, dv = sin(πt) dt

du = 1 dt, v = (-1/π) cos(πt).


So, ∫(t = 2 to 3) t sin(πt) dt

= (-1/π) t cos(πt) {for t = 2 to 3} - ∫(t = 2 to 3) (-1/π) cos(πt) dt

= (-1/π) (3 * -1 - 2 * 1) + [(1/π^2) sin(πt) {for t = 2 to 3}]

= 5/π + 0

= 5/π.

Therefore,

∫(t = 2 to 3) <t^3, t√(t - 2), t sin(πt)> dt = <65/4, 26/15, 5/π>.

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