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4 years ago

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The function 3(2)t models the number of leaves on a plant, where t represents the number of weeks since it was planted. Which st

atement is the best interpretation of one of the values in this function? A) The number of leaves increases by 6 each week. B) The initial number of leaves on the plant was 2. C) The initial number of leaves on the plant was 3. D) The number of leaves on the plant increases by 3% each week.

1 answer:

LUCKY_DIMON [66]4 years ago

3 0

Answer:

C) The initial number of leaves on the plant was 3.

Step-by-step explanation:

The plant has initially 3 leaves and is multiplied by 2 every week. Therefore, the answer is C.

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Solve the equation 3 - 4-587<br> 3.87<br> b. 0.55, -0.55<br> a.<br> C. 1.53,-1.53<br> d. 4.98

dexar [7]

Answer: X = 0

Let me know if it’s correct

8 0

3 years ago

.help me with this please thanks

aev [14]

I would say B .
They are not like terms because they are not all the same

5 0

3 years ago

Im not sure if anyone knows how to do this but if u do could u pleaseee help me with this!!!

slavikrds [6]

Answer:

y = -2x - 5

Step-by-step explanation:

<u>1) Find the slope of the line.</u>

The slope of the original line is the same as the slope of the parallel line.

Slope formula:

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

In this case you can choose any 2 set of points on the table.

$m = \frac{4 - 2}{-3 - (-2)}$ = $\frac{4 - 2}{-3 + 2}$ = $\frac{2}{-1}$ = -2

So the slope of the line is -2

<u>2) Use the point-slope formula to find the equation of the line.</u>

Point-slope formula:

$y - y_{1} = m(x - x_{1})$

Now plug in the point (0, -5) and the slope -2 into the equation.

y - (-5) = -2(x - 0)

y + 5 = -2(x - 0)

To solve the equation first apply the distributive property.

y + 5 = -2x + 0

y + 5 = -2x

Next, subtract 5 from sides.

y = -2x - 5

You know have your equation in point-slope form!

6 0

3 years ago

Suppose the test scores for a college entrance exam are normally distributed with a mean of 450 and a s. d. of 100. a. What is t

svet-max [94.6K]

Answer:

a) 68.26% probability that a student scores between 350 and 550

b) A score of 638(or higher).

c) The 60th percentile of test scores is 475.3.

d) The middle 30% of the test scores is between 411.5 and 488.5.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 450, \sigma = 100$

a. What is the probability that a student scores between 350 and 550?

This is the pvalue of Z when X = 550 subtracted by the pvalue of Z when X = 350. So

X = 550

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{550 - 450}{100}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

X = 350

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{350 - 450}{100}$

$Z = -1$

$Z = -1$ has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

68.26% probability that a student scores between 350 and 550

b. If the upper 3% scholarship, what score must a student receive to get a scholarship?

100 - 3 = 97th percentile, which is X when Z has a pvalue of 0.97. So it is X when Z = 1.88

$Z = \frac{X - \mu}{\sigma}$

$1.88 = \frac{X - 450}{100}$

$X - 450 = 1.88*100$

$X = 638$

A score of 638(or higher).

c. Find the 60th percentile of the test scores.

X when Z has a pvalue of 0.60. So it is X when Z = 0.253

$Z = \frac{X - \mu}{\sigma}$

$0.253 = \frac{X - 450}{100}$

$X - 450 = 0.253*100$

$X = 475.3$

The 60th percentile of test scores is 475.3.

d. Find the middle 30% of the test scores.

50 - (30/2) = 35th percentile

50 + (30/2) = 65th percentile.

35th percentile:

X when Z has a pvalue of 0.35. So X when Z = -0.385.

$Z = \frac{X - \mu}{\sigma}$

$-0.385 = \frac{X - 450}{100}$

$X - 450 = -0.385*100$

$X = 411.5$

65th percentile:

X when Z has a pvalue of 0.35. So X when Z = 0.385.

$Z = \frac{X - \mu}{\sigma}$

$0.385 = \frac{X - 450}{100}$

$X - 450 = 0.385*100$

$X = 488.5$

The middle 30% of the test scores is between 411.5 and 488.5.

7 0

3 years ago

How does the measure of the pink inscribed angle compare with the measure of the blue intercepted arc? How do you know?

Goryan [66]

Answer:

The pink angle is half the angle subtended by the blue arc.

Step-by-step explanation:

Given

See attachment for circle

Required

Compare the pink angle to the blue arc

Let the pink angle be x and the angle subtended by the blue arc be y.

So, we have:

$x \to$ angle at circumference

$y \to$ angle subtended by arc

The relationship between x and y is:

$y =2x$

Make x the subject

$x = \frac{1}{2}y$

7 0

3 years ago