Question

Write the complete balanced equation for the reaction between barium metal (Ba) and nitrogen gas (N2). You do not need to make the subscripts smaller; just write them out as regular numbers. For example: N2.

Answer 1

3Ba + N2 -----> Ba3N2

Ba is in the second group and metal, its charge = +2 in the compound.

N is non-metal, it is in 15th group, so it has 5 electrons on the last level, so it can take 3 electrons more(8-5=3). N has charge (-3) in compound.

Ba and N form compound Ba3N2.

Answer 2

Answer: $3Ba(s)+N_2(g)\rightarrow Ba_3N_2(s)$

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced chemical equation for reaction between barium and itrogen gas is:

$3Ba(s)+N_2(g)\rightarrow Ba_3N_2(s)$

where (s) stands for solid state and (g) stands for gaseous state.