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gulaghasi [49]
3 years ago
8

Equal volumes of two monoprotic acid solutions (A and B) are titrated with identical NaOH solutions. The volume to reach the equ

ivalence point for solution A is twice the volume required to reach the equivalence point for solution B, and the pH at the equivalence point of solution A is higher than the pH at the equivalence point for solution B. Which statement is true?
A) The acid in solution A is less concentrated than in solution B and is also a weaker acid than that in solution B.
B) The acid in solution A is more concentrated than in solution B and is also a stronger acid than that in solution B.
C) The acid in solution A is less concentrated than in solution B and is also a stronger acid than that in solution B.
D) The acid in solution A is more concentrated than in solution B and is also a weaker acid than that in solution B.
Chemistry
2 answers:
Firlakuza [10]3 years ago
5 0

Answer:

D

Explanation:

It looks like two things are being looked at here; the concentration and strength of acid. Titrations show volume and are not affected by the strength of the acid, so let's start with that. Since twice the volume of NaOH is needed to reach equivalence point, there must be a higher concentration of A, as the chemical equation must be the same (it says that they're both monoprotic acids, so the chemical equation doesn't change). This eliminates A and C.

As for pH; if it is higher at equivalence point, it wasn't as strong at moving the pH down despite being in NaOH(a strong base); and since solution A has a higher pH at equivalence point, it isn't as strong as solution B.

This eliminates B.

The answer is D.

This seems like a normal AP Chemistry question, but then again titrations are important to know in chemistry.

agasfer [191]3 years ago
4 0

Answer:

D. Solution A has more concentrated acid than solution B and acid in solution A is also a weaker acid than that in solution B.

Explanation:

As it has been said in the question that the volume to reach the equivalence point of the solution A is twice the volume of solution B, this is because the acid in the solution A is more concentrated than B that's why more NaOH was required to reach to the equivalence point.

Since the pH at the equivalence point was greater for solution A that means the acid in solution A was a weak acid that's why the pH raised more as the NaOH was added to the solution.

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Which of the following reactions have a positive ΔSrxn? Check all that apply.
PolarNik [594]

Answer:

The reactions that have a <em>positive ΔS rxn </em>are the first and the fourth choices:

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  • <em>2A(g) + 2B(g) → 5C(g)</em>

Explanation:

<em>ΔS rxn </em>is the change of entropy of the chemical reaction.

ΔS rxn = S after reaction - S before reaction.

Therefore, a positive ΔS rxn  means that the entropy after the reaction is greater than the entropy before the reaction.

You may use some assumptions to predict whether a reaction will lead an increase or decrease of the entropy.

First, assume that all the non-shown conditions, such as temperature and pressure, are constant.

Under that assumption, and from the meaning of entropy as a measure of the disorder or randomness of a system you can predict the sign of the change of entropy.

  • <em><u>2A(g) + B(s) → 3C(g)</u></em>

        1)  The solid compounds, B(s) in this case, are very ordered and so they have low entropy.

        2) Gas molecules are highly disordered (scattered), and the greater the number of molecules of the gas the larger the entropy, S).

Hence, since the product side shows 3 gas molecules and the reactant side shows 2 gas molecules and 1 solid molecule, you predict that the products have a larger entropy than the reactants, meaning an increase in entropy: <em>ΔS rxn is positive.</em>

  • <em><u>2A(g) + B(g) → C(g)</u></em>

Using the same reasoning, 3 gas molecules in the  reactant side have more entropy than 1 molecule in the product side, and so the reaction leads to a decrease in the entropy: ΔS rxn is negative

  • <u><em>A(g) + B(g) → C(g)</em></u>

Again, 2 gas molecules in the  reactant side have more entropy than 1 molecule in the product side, and so the reaction leads to a decrease in the entropy: ΔS rxn is negative

  • <u><em>2A(g) + 2B(g) → 5C(g)</em></u>

With the same reasoing, 5 molecules in the product side, lets you predict that will have more entropy than 4 molecules in the reactant side, and, the entropy will increase: <em>ΔS rxn is positive.</em>

6 0
3 years ago
What is the specific heat of the solid phase? (Please see picture attached)
ValentinkaMS [17]

Answer:

B.0.2 J/g°C

Explanation:

From the attached picture;

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We are required to determine the specific heat capacity of the substance;

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Rearranging the formula;

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Therefore;

Specific heat = 200 J ÷ (20 g × 50°c)

                      = 0.2 J/g°C

Thus, the specific heat of the solid is 0.2 J/g°C

4 0
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