Your first step should be to analyse the compound. For example, if the compound is carbon, you know it always has a valence of four, so, if it has a formula C2H4 (ethylene) it obviously has a double bond. There are difficulties here because benzene C6H6 can be considered to have 6 1.5 C-C bonds, being aromatic.
A second step is to look at its structure. Double bonds are traditionally shorter than single bonds; triple bonds shorter still. Covalent bonds do have typical lengths, nevertheless you can still have problems.
<span>A third step is to consider reactivity. For example, if you have a C=C double bond, you can add, say, bromine to it Thus C2H4 gives C2H4Br2, and by adding two bromine atoms you know you have one double bond. Again, benzene becomes an awkward molecule, but because of this, you know benzene does not have double bonds in the traditional sense</span>
Answer:
Carbon < Lithium < Beryllium < Oxygen < Fluorine
Explanation:
Answer:
[Ar]3d^{10}4s^{2}4p^{6}
Explanation:
Electronic Configuration of Bromine : [Ar]3d^{10}4s^{2}4p^{5}
At oxidation state -1, electronic Configuration of Bromine : [Ar]3d^{10}4s^{2}4p^{6}
An element with an atomic number 12 has 12 protons.
atomic number=number of protons.
Answer:
Beacause it does just in a different place
Explanation:
