Answer:
So, the sample mean is 31.3.
So, the sample standard deviation is 6.98.
Step-by-step explanation:
We have a list of data for the speeds (in miles per hour) of the 20 vehicles. So, N=20.
We calculate the sample mean :

So, the sample mean is 31.3.
We use the formula for a sample standard deviation:

Now, we calculate the sum

Therefore, we get

So, the sample standard deviation is 6.98.