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mariarad [96]
3 years ago
13

Which expression is equivalent to (8 a minus 3 b + 7) minus (2 a + b minus 4)? 6 a minus 2 b + 11 6 a minus 4 b + 3 6 a minus 2

b + 3 6 a minus 4 b + 11

Mathematics
2 answers:
bekas [8.4K]3 years ago
6 0
This is how it turns out:

saul85 [17]3 years ago
6 0

The answer is 6a - 4b+ 11

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Plz help I need this now right answer will get brianliest
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That’s a supplementary triangle which means it would have to equal 180 so the answer is 66
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Read 2 more answers
Sinx(cscx-sinx)=cos^2x
Yuri [45]

\bf sin(x)[csc(x)-sin(x)]~~=~~cos^2(x) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin(x)\left[\cfrac{1}{sin(x)}-\cfrac{sin(x)}{1} \right]\implies \underline{sin(x)}\left[\cfrac{1-sin^2(x)}{\underline{sin(x)}} \right] \\\\\\ 1-sin^2(x)\implies cos^2(x)


recall again, sin²(θ) + cos²(θ) = 1.

3 0
3 years ago
Evaluate tan ( cos^-1 ( 1/8 ) ) , giving your answer as an exact value (no decimals)
vekshin1

\bf cos^{-1}\left( \cfrac{1}{8} \right)=\theta \qquad \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{8}}\impliedby \textit{let's find the \underline{opposite}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{8^2-1^1}=b\implies \pm\sqrt{63}=b ~\hfill tan(\theta )=\cfrac{\stackrel{opposite}{\pm\sqrt{63}}}{\stackrel{adjacent}{1}} \\\\\\ ~\hspace{34em}


\bf \stackrel{\textit{keeping in mind that}}{tan\left(cos^{-1}\left( \frac{1}{8} \right) \right)}\implies tan(\theta )

5 0
3 years ago
Which polynomial is a product of (3x+2) and (x-7)
pogonyaev

(3x+2)  (x-7)

FOIL

first 3x*x  = 3x^2

outer  3x*-7 = -21x

inner = 2*x = 2x

last  2*-7 = -14

add them together  = 3x^2 -21x+2x -14

combine like terms  3x^2 -19x -14

5 0
3 years ago
Mrs. Martini is 6 years more than 3 times as old as Tony. Eight years ago, she
zalisa [80]

Mrs Martini age is 42 years and Tony age is 12 years

Step-by-step explanation:

The given is:

  • Mrs. Martini is 6 years more than 3 times as old as Tony
  • Eight years ago, she  was 2 years less than 9 times as old as he was then

Assume that Tony is x years old now

∵ Mrs. Martini is 6 years more than 3 times as old as Tony

∵ Tony is x years old

- Multiply the age of Tony by 3 and add 6 to the product

∴ The age of Mrs Martini = 3 x + 6

8 years ago

- Subtract 8 from the age of each one

Tony age = (x - 8)

Mrs Martini age = (3 x + 6) - 8 = 3 x + 6 - 8 = 3 x - 2

∵ Eight years ago, Mrs Martini was 2 years less than 9 times as old

  as Tony was then

- Multiply Tony age by 9 and subtract 2 from the product

∵ Tony age from 8 years ago = x - 8

∵ Mrs Martini age from 8 years ago = 3 x - 2

∴ 9(x - 8) - 2 = 3 x - 2

- Simplify the left hand side

∴ 9 x - 72 - 2 = 3 x - 2

- Add like terms

∴ 9 x - 74 = 3 x - 2

- Subtract 3 x from both sides

∴ 6 x - 74 = -2

- Add 74 to both sides

∴ 6 x = 72

- Divide both sides by 6

∴ x = 12

∵ x represents the age of Tony

∴ Tony is 12 years old

∴ 3 x + 6 is the age of Mrs Martini

- Substitute x by 12

∵ 3(12) + 6 = 36 + 6 = 42

∴ Mrs Martini is 42 years old

Mrs Martini age is 42 years and Tony age is 12 years

Learn more:

You can learn more about word problems in brainly.com/question/10557938

#LearnwithBrainly

6 0
3 years ago
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