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3 years ago

What is the value of sinC ?

Mathematics

2 answers:

Sever21 [200]3 years ago

8 0

Answer:

$sin \:C =\frac{8}{17}$

Step-by-step explanation:

In a right triangle, the sine of an angle is the length of the opposite side divided by the length of the hypotenuse.

$sin \:x =\frac{O}{H}$

From the formula above we know that the sine of an angle is the opposite side divided by the hypotenuse. The opposite side is AB and has a length of 8. The hypotenuse is AC with a length of 17. So we can write

$sin \:C =\frac{8}{17}$

Vlada [557]3 years ago

7 0

SinC=(8/17)
solve for C = arcsin(8/17)

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Nataliya [291]

Answer:

One step Equations:

1. x=4

2. x=18

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Two Step Equations:

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2. x= -4

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3 0

3 years ago

Read 2 more answers

A newborn weighs 8 pounds, 5 ounces. There are 453.59 grams per pound. What is the infant's weight in grams?

Nadya [2.5K]

Convert from Oz and Lbs.

1 Pound = 453.59237 Grams

1 Ounce = 28.3495231 Grams

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141.7476155 for Oz

Add them, and you get:

3770.4865755

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Hope this helped, and have a good day!

5 0

3 years ago

Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

$y'(x)= x^2y(x)-\frac12y^2(x)$

Putting the value of y'(x) in equation (1)

$y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))$

Substituting x =0 and h= 0.2

$y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]$

$\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]$ [∵ y(0) =3 ]

$\Rightarrow y(0.2)\approx 2.7$

Substituting x =0.2 and h= 0.2

$y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]$

$\Rightarrow y(0.4)\approx 2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]$

$\Rightarrow y(0.4)\approx 1.9926$

Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

$\Rightarrow y(0.6)\approx 1.6593$

Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

$\Rightarrow y(0.6)\approx 0.8800$

Substituting x =0.8 and h= 0.2

$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

$\Rightarrow y(1.0)\approx 0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]$

$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

4 0

3 years ago

planes x and y and points J, K, L, M and N are shown. exactly hiw many points contain points J, K, and N ? 0 1 2 3

Studentka2010 [4]

Answer:3

Step-by-step explanation:

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3 years ago

1. The curve y = (x - 1)(x – 5) cuts the x-axis at A and B and the y-axis at C.

saveliy_v [14]

So the first two questions are asking for points of intercept. a is asking where the function crosses the x, in this case it is where y=0. So your x intercept is at x= 1,5. Then to find the y intercept it is where x=0, so just substitute 0 for x. Then you get your y intercept as y=5. Because your coefficient for the quadratic function is positive your function has a minimum since it opens upward. I’m not sure what is means by C coordinate, but your vertex is at (3,-4) and lime of symmetry is at x=3.

X intercepts: (1,0) and (5,0)
Y intercept: (0,5)

3 0

3 years ago