Answer:
B. GRID COMPUTING , ON - DEMAND COMPUTING AND REAL TIME COMPUTING
Explanation:
Grid computing, on-demand computing and real time computing are currently the most impactful information technology processes. The Grid computing from example entails distributed computing whereby computing resources are distributed across different systems for a computing task. This is seen in server systems where a super virtual computer composed of a network of computers are connected to share resources and perform large tasks. This form of computing has majorly affected and improved complex computing tasks today.
On demand and real time computing are also other notable trends in IT with real time computing bringing the power of live and direct coverage of information to our screens and on demand making it possible for the average user to access computing resources as needed such as in the services of cloud computing providers
Answer:
The correct answer to this question is: "this program give an error".
int i = 7; //declare a variable(i) and assign value.
while (i>=2) //use loop and check condition.i greater then equal to 2.
{
System.out.print (i +""); //print value of i.
if ((i%3) == 0) //hold remainder
{
i +2; //error.
}
else
{
i/=2; //hold Quotient
}
}
Explanation:
In the above program, there is an error in the if block because it is not the correct way to declare. To use the variable from the correct output we use a variable like this.
Example
int i = 7;
//declare a variable(i) and assign value.
while (i>=2)
//use loop and check condition.i greater then equal to 2.
{
System.out.print (i +""); //print value of i.
if ((i%3) == 0) //hold remainder
{
i =i+2;
}
else
{
i/=2; //hold Quotient
}
}
Output: 732
Answer: A parameter or a formal argument is used
Answer:
The C code is explained below. The highlighted code represents the "your solution goes here" section
Explanation:
//Header file section
#include <stdio.h>
//Program begins with a main method
int main(void)
{
//Declare the integer variables
int userNum1;
int userNum2;
//Initialized the values to the variables
userNum1 = 1;
userNum2 = 14;
// If userNum1 is less than 0, then print "userNum1 is negative".
// '\n' represents end with newline
if (userNum1<0)
{
printf("userNum1 is negative. \n");
}
//If userNum2 is greater than 10, then convert userNum2 to 0.
//Otherwise, print "userNum2 is less than or equal to 10"
if (userNum2>10)
{
userNum2 = 0;
}
else
{
printf("userNum2 is less than or equal to 10.");
//'\n' represents end with newline
printf("\n");
}
//Print userNum2 value
printf("userNum2 is %d. \n", userNum2);
return 0;
}
Virtualization. To enable easy deployment and scalability, it should be easy to spin up new machines on request. Virtualization offers the possibility to clone operating systems and deploy solutions independent of the actual hardware.