1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sonja [21]
3 years ago
8

Please help me solve the problem

Mathematics
1 answer:
zavuch27 [327]3 years ago
3 0

Answer:

f(2) = 7/4

Step-by-step explanation:

f(x) =  \frac{2x + 7 -  {x}^{2} }{4}  \\ f(2) =  \frac{2(2) + 7 -  {2}^{2} }{4}  \\ f(2) =  \frac{4 +  7- 4}{4}  \\ f(2) =  \frac{7}{4}

You might be interested in
Meagan is buying a large box from the post office to send a birthday gift to her grandmother in Enid, Oklahoma. The dimensions o
IRISSAK [1]

Answer:

Hmm this is hard lemme think

Step-by-step explanation:

The answer should be 18 vol. bc it said what is the biggest gift she can send her grandma

6 0
3 years ago
Read 2 more answers
Please help I think its 16 but not sure
Stels [109]

Answer:

I think its 12 to this question

6 0
3 years ago
In a metal fabrication​ process, metal rods are produced to a specified target length of 15 feet. Suppose that the lengths are n
Leto [7]

Answer:

95% Confidence interval: (14.4537 ,15.1463)

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 feet

Sample mean, \bar{x} = 14.8 feet

Sample size, n = 16

Alpha, α = 0.05

Sample standard deviation, σ = 0.65 feet

Degree of freedom = n - 1 = 15

95% Confidence interval:

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 15 and}~\alpha_{0.05} = \pm 2.1314  

14.8 \pm 2.1314(\dfrac{0.65}{\sqrt{16}} ) \\\\= 14.8 \pm 0.3463 = (14.4537 ,15.1463)  

is the required confidence interval for the true mean length of rods.

3 0
3 years ago
Read 2 more answers
Dimensional analysis: How many atoms are in a kilogram of silver, if there are 6.02 x 10^23 atoms per mole and silver weighs 107
kondor19780726 [428]

Answer:

5.58×10²⁴ atoms.

Step-by-step explanation:

From the question given above, the following data were obtained:

1 mole of silver = 107.9 g

Number of atoms in 1 mole of silver = 6.02×10²³ atoms.

Number of atoms in a kilogram of silver =.?

Next, we shall convert 1 kg of silver to grams (g). This can be obtained as follow:

1 kg = 1000g

Therefore, 1 kg of silver is equivalent to 1000g.

Finally, we shall determine the number of atoms in 1 kg (i.e 1000 g) of silver as follow:

107.9 g of silver contains 6.02×10²³ atoms.

Therefore, 1000 g of silver will contain = (1000 × 6.02×10²³) / 107.9 = 5.58×10²⁴ atoms.

Thus, a kilogram of silver contains 5.58×10²⁴ atoms.

6 0
3 years ago
a guy is washing 32 feet off the ground. he positions the ladder at an angle of 67° with the ground. how tall is the ladder
irina [24]

Answer:

34.76 feet

Step-by-step explanation:

trig

SOH CAH TOA

6 0
3 years ago
Other questions:
  • Help with this question please!
    6·1 answer
  • How do I do this I don’t know how
    12·1 answer
  • What is the fraction and decimal of25%
    11·2 answers
  • write a division equation to represent the repeated subtraction 32 take away 8 is 24 24 take away 8 is16 16 take away 8 is 8/8 t
    7·1 answer
  • What is 1/2 divided by 3/2 equals out to be in fraction form?
    13·1 answer
  • I need the answer please
    10·2 answers
  • Question 4 4 pts Lori buys a $1500 certificate of deposit (CD) that earns 6% interest that compounds monthly. How much will the
    10·1 answer
  • Last year at RT University, the ratio of the number of
    9·1 answer
  • PLEASE HELP (ASAP)
    9·2 answers
  • Converting between scientific notation and standard form in a real-world situation
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!